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3 years ago

Factoring trinomial Bsquared+10b+25

Mathematics

2 answers:

salantis [7]3 years ago

7 0

(B+5)(B+5) Is the correct factorization.

vovangra [49]3 years ago

7 0

B^2 + 10b +25
(b+5) (b+5)
The reason is FOILing
First, multiply the two first numbers of each binomial
(b*b) = b^2
Next, multiply the outer numbers/terms
(b*5) = 5b
Then, multiply the outer terms:
(5*b) = 5b
Finally, multiply the last terms
(5*5) = 25
Then, put it all together
b^2 + 5b + 5b +25
Simplify (add like terms)...
b^2 + 10b + 25
Therefore, your answer is:
b^2 + 10b + 25 = (b+5) (b+5)

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Answer:

<h2>A.Multiplication Property of Equality</h2>

Step-by-step explanation:

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3 years ago

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What is the equation of the line that passes through the point (-3,2) and has a slope of -2/3

Nookie1986 [14]

Answer:

Y=-2/3x+0

This is the answer I found

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3 years ago

2. Which sign makes the statement true?<br>00w

Furkat [3]

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4 years ago

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A student committee is to consist of 2 freshmen, 5 sophomores, 4 juniors, and 3 seniors. If 6 freshmen, 13 sophomores, 8 juniors

mezya [45]

<h3>Answer: 491,891,400</h3>

Delete the commas if necessary.

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Explanation:

There are 6 freshmen total and we want to pick 2 of them, where order doesn't matter. The reason it doesn't matter is because each seat on the committee is the same. No member outranks any other. If the positions were labeled "president", "vice president", "secretary", etc, then the order would matter.

Plug n = 6 and r = 2 into the nCr combination formula below

$n C r = \frac{n!}{r!(n-r)!}\\\\6 C 2 = \frac{6!}{2!*(6-2)!}\\\\6 C 2 = \frac{6!}{2!*4!}\\\\6 C 2 = \frac{6*5*4!}{2!*4!}\\\\ 6 C 2 = \frac{6*5}{2!}\\\\ 6 C 2 = \frac{6*5}{2*1}\\\\ 6 C 2 = \frac{30}{2}\\\\ 6 C 2 = 15\\\\$

This tells us there are 15 ways to pick the 2 freshmen from a pool of 6 total.

Repeat those steps for the other grade levels.

n = 13 sophomores, r = 5 selections leads to nCr = 13C5 = 1287. This is the number of ways to pick the sophomores.

You would follow the same type of steps shown above to get 1287. Let me know if you need to see these steps.

Similarly, 8C4 = 70 is the number of ways to pick the juniors.

Lastly, 14C3 = 364 is the number of ways to pick the seniors.

-----------------------------

To recap, we have...

15 ways to pick the freshmen
1287 ways to pick the sophomores
70 ways to pick the juniors
364 ways to pick the seniors

Multiply out those values to get to the final answer.

15*1287*70*364 = 491,891,400

This massive number is a little under 492 million.

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2 years ago

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