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2 years ago

The two polygons are similar. Find the measure of angle U. 120° 185°

Mathematics

1 answer:

mash [69]2 years ago

7 0

It’s 80 for sure Ik this one

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A line with a slope of 0 contains the point (3,4) . The point -2,? is also on the line. What is the missing y-coordinate?

KatRina [158]

Answer:

Step-by-step explanation:

If the slope is 0, the line is horizontal and the y-coordinate is 4 for all x values.

Thus the missing y-coordinate is 4.

8 0

3 years ago

What is the behavior of?

GarryVolchara [31]

Answer:

i thin its option 1 or 2 because by looking at the problem it kinda click after starring at it for awhile

i hope this useful in a way

5 0

3 years ago

Read 2 more answers

You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perime

Anna71 [15]

Answer:

5 feet

Step-by-step explanation:

P = 2(w + l)

P = 34

l = w + 7

34 = 2 (w + w + 7)

34 = 2w + 2w + 14

34 - 14 = 4w

20 = 4w

w = 5 feet

Since l = w + 7

l = 5 + 7

l = 12 feet

5 0

3 years ago

Any portion of the circumference of a circle is called a(n)

Alex777 [14]

Any portion of the circumference of a circle is called a radius

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3 years ago

From a point A that is 8.20 m above level ground, the angle of elevation of the top of a building s 31 deg 20 min and the angle

Mariulka [41]

Answer:

30.11 meters ( approx )

Step-by-step explanation:

Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )

Given,

Point A is 8.20 m above level ground,

So, the height of the building = ( x + 8.20 ) meters,

Now, 1 degree = 60 minutes,

⇒ $1\text{ minute } =\frac{1}{60}\text{ degree }$

$20\text{ minutes }=\frac{20}{60}=\frac{1}{3}\text{ degree}$

$50\text{ minutes }=\frac{50}{60}=\frac{5}{6}\text{ degree}$

By the below diagram,

$tan ( 12^{\circ} 50') = \frac{8.20}{y}$

$tan(12+\frac{5}{6})^{\circ}=\frac{8.20}{y}$

$tan (\frac{77}{6})^{\circ}=\frac{8.20}{y}$

$\implies y=\frac{8.20}{tan (\frac{77}{6})^{\circ}}$

Now, again by the below diagram,

$tan (31^{\circ}20')=\frac{x}{y}$

$tan(31+\frac{1}{3})=\frac{x}{y}$

$\implies x=y\times tan(\frac{94}{3})=\frac{8.20}{tan (\frac{77}{6})^{\circ}}\times tan(\frac{94}{3})^{\circ}=21.9142943216\approx 21.91$

Hence, the height of the building = x + 8.20 = 30.11 meters (approx)

8 0

3 years ago