Please help im not good with trig
1 answer:
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Answer:
-The ordered pair (-1, 5) is a solution to the first equation because it makes the first equation true.
-The ordered pair (-1, 5) is a solution to the second equation because it makes the second equation true.
-The ordered pair (-1, 5) is a solution to the system because it makes both equations true
Step-by-step explanation:
<u><em>The correct question is</em></u>
Which statements are true about the ordered pair (−1, 5) and the system of equations?
x+y=4
x−y=−6
we know that
If a ordered pair is a solution of a equation, then the ordered pair, must satisfy the equation (makes the equation true)
If a ordered pair is a solution of the system of equations, then the ordered pair, must satisfy the equations of the system (makes both equations true)
we have
----> first equation
----> second equation
step 1
<u><em>Verify if the ordered pair satisfy the first equation </em></u>
Substitute the values of x and y of the ordered pair in the first equation
For x=-1, y=5
---> is true
The ordered pair satisfy the first equation
so
<em>The ordered pair is a solution to the first equation because it makes the first equation true</em>
step 2
<u><em>Verify if the ordered pair satisfy the second equation </em></u>
Substitute the values of x and y of the ordered pair in the second equation
For x=-1, y=5
---> is true
The ordered pair satisfy the second equation
so
<em>The ordered pair is a solution to the second equation because it makes the second equation true</em>
therefore
<em>The ordered pair (-1, 5) is a solution to the system because it makes both equations true</em>
Using Pythagorean theorem, the student walked 53.58 meters more compared to the total displacement from the starting point.
If a student walks 100 meters north, then 100 meters west, then the path he travels resembles the sides of a right triangle (see attached photo).
Using Pythagorean theorem, we can solve for the total displacement from the starting point to the end point.
c^2 = a^2 + b^2
where c is the total displacement from the starting point to the end point
a is the distance he walks up north
b is the distance he walks to the west
c^2 = 100^2 + 100^2
c^2 = 10,000 + 10,000
c^2 = 20,000
c = 141.42 meters
Comparing the total distance the student walked and the total displacement from the starting point to the end point by subtraction.
100 meters + 100 meters - 141.42 meters = 53.58 meters
Learn more about Pythagorean Theorem here: brainly.com/question/343682
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Sorry if im to late but these were the right answers
