Question

Question (in need of help)

Answer 1

Required Answer:-

This is an right angle ∆ and the side lengths containing a right angle are 9 and 11.

By Pythagoras theoram,

${p}^{2} + {b}^{2} = {h}^{2}$

where p is the perpendicular, b is the base and h is the hypotenuse.

Plugging the values,

${9}^{2} + {11}^{2} = {h}^{2}$

Then,

$h = \sqrt{ {9}^{2} + {11}^{2} }$

$h = 14.12(approx.)$

Hence:-

The x of the right angled ∆ = 14.12

Answer 2

Answer:

the top angle is 11 and the angle on the left is 9 so the X will be rounded to the nearest hundreth since it's the biggest angle so 11×9=109 so yea I THINK its 100 since it's rounding