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Mademuasel [1]
3 years ago
5

Question (in need of help)

Mathematics
2 answers:
mr Goodwill [35]3 years ago
6 0
<h3><u>Required</u><u> Answer</u><u>:</u><u>-</u></h3>

This is an right angle ∆ and the side lengths containing a right angle are 9 and 11.

By Pythagoras theoram,

{p}^{2}  +  {b}^{2}  =  {h}^{2}

where p is the perpendicular, b is the base and h is the hypotenuse.

Plugging the values,

{9}^{2}  +  {11}^{2}  =  {h}^{2}

Then,

h =  \sqrt{ {9}^{2}  +  {11}^{2} }

h = 14.12(approx.)

<h3><u>Hence:</u><u>-</u></h3>

The x of the right angled ∆ = <u>1</u><u>4</u><u>.</u><u>1</u><u>2</u>

Black_prince [1.1K]3 years ago
3 0

Answer:

the top angle is 11 and the angle on the left is 9 so the X will be rounded to the nearest hundreth since it's the biggest angle so 11×9=109 so yea I THINK its 100 since it's rounding

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