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3 years ago

Indicate a general rule for the nth term of this sequence. 12a, 15a, 18a, 21a, 24a, . . .

1 answer:

3 0

It is an arithmetic progression. Note the general rule for AP sequences:

a(n) = a(1) + (n - 1)d
a(1) = 12a (first term)
d = 3a (common difference)

General rule: a(n) = 12a + (n - 1)*3a

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Solve the equation x-20.7=9.5 for x

kenny6666 [7]

The answer will come out to 30.2

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2 years ago

Read 2 more answers

Jonah was standing at an elevation somewhere between-1 1/2

erma4kov [3.2K]

Answer:

$=-\frac{23}{12},\ -2$ and many others

Step-by-step explanation:

The limits given for Jonah's elevation with regards to sea level are

$-1\frac{1}{2}$ and $-2\frac{1}{3}$

Any number belonging to that interval could be the requested answer. We'll pick the exact center (mean value) between them:

$-1\frac{1}{2} =-\frac{3}{2}$

$-2\frac{1}{3}=-\frac{7}{3}$

Computing the mean value:

$\frac{1}{2}\left (-\frac{3}{2}-\frac{7}{3} \right)$

$=\frac{1}{2}\left (-\frac{23}{6}\right)$

$=-\frac{23}{12}$

Since $-2\frac{1}{3}=-2.33$

And $-1\frac{1}{2}=-1.5$

Other numbers like -1.6,-2,-2,3 can be examples of the required answer

8 0

3 years ago

the slope of the line below is -1. write the point-slope equation of the line using the coordinates of the labeled point. (7, -7

Doss [256]

Answer:

y + 7 = -(x - 7)

Step-by-step explanation:

point slope is written in the form y - y₁ = m(x - x₁)

substitute -1 for m, 7 for x₁ and -7 for y₁

4 0

2 years ago

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is

anastassius [24]

Answer:

The rate of change of temperature is 1.29 degree Celsius per second.

Step-by-step explanation:

We are given the following information in the question:

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius where x and y are measured in centimeters.

$x = \sqrt{2+t}\\\\y = 5 + \displaystyle\frac{1}{14}t$

$T_x(4,6) = 8, T_y(4,6) = 4$

We have to find the rate at which the temperature is rising on the bug's path after 14 seconds.

At t = 14 seconds, we have,

$x = \sqrt{2+14} = 4\\\\y = 5 + \displaystyle\frac{1}{14}(14) = 5+1 = 6$

To find rate of change of temperature, we differentiate,

$\displaystyle\frac{dT}{dt} = \frac{dT}{dx}\frac{dx}{dt} + \frac{dT}{dy}\frac{dy}{dt}\\\\\displaystyle\frac{dT}{dt} = T_x(x,y)(\frac{1}{2\sqrt{2+t}}) + T_y(x,y)\frac{1}{14}\\\\At~ t = 14, x = 4, y = 6\\\\\frac{dT}{dt} = T_x(4,6)(\frac{1}{2\sqrt{2+t}}) + T_y(4,6)\frac{1}{14}\\\\\frac{dT}{dt} = 8\times \frac{1}{8} +4\times \frac{1}{14} = 1 + 0.2857 = 1.2857$

Thus, the rate of change of temperature is 1.29 degree Celsius per second.

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3 years ago

Daca a supra b = 3 supra 7 , calculati 3a+ 8b supra 8 b si 5a supra 5a+6b

Pavel [41]

What language is it? can't read

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3 years ago