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Alina [70]
2 years ago
11

If angle B measures 25°, what is the approximate perimeter of the triangle below? A right triangle is shown. Angle A is 90 degre

es and angle B is 25 degrees. Side A B has a length of 4.

Mathematics
1 answer:
Bad White [126]2 years ago
4 0

Answer:

Perimeter of the triangle = 10.48 unit

Step-by-step explanation:

From the ΔABC

∠A = 90°

∠B = 25°

∠C = 180-90-25 = 65°

AB = 4 unit

From the sine rule

\frac{4}{\sin65} = \frac{AC}{\sin25} = \frac{BC}{\sin65}

AC = 4 (\frac{\sin25}{\sin65} )

AC = 1.86 unit

BC = 4 (\frac{ \sin90}{\sin60} )

BC = 4.62 unit

Perimeter of the triangle = AB + BC + CA

Perimeter of the triangle = 4 + 4.62 + 1.86

Perimeter of the triangle = 10.48 unit

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Answer:

f=1

Step-by-step explanation:

Let start off with doing -f plus 4f which gives you 3f. The equation would now be 2+3f=8-3f. Add 3f so you can cancel out the -3f and add the 3f to the other 3f. Now your equation is 2+6f=8. Cancel out do by doing -2. (Don't forget to to it to the 8 also.) Now your equation is 6f=6. Divide 6 from both sides to get 1. (You divide because you want to get f alone.

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The square root of 7 lies between what two numbers
ExtremeBDS [4]

The square root of 7 would like between 2 and 3. This is because 2 x 2 is 4's square root and 3 x 3 is nine's square root. Seven is between four and nine.

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Vlad [161]

Answer:

The answer is B

Step-by-step explanation:

x/-y is equivalent to -(x/y)

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C(1,-2)

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A maritime flag is shown. What is the area of the shaded part of the flag? Explain
Rom4ik [11]

Answer:

<em></em>Area = 72in^2<em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

<em></em>Area_2 = 8in * 12in<em></em>

<em></em>Area_1 = 96in^2<em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em>Area_2 = \frac{1}{2} * base * height<em></em>

<em></em>Area_2 = \frac{1}{2} * (6in + 6in) * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 12in * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 48in^2<em></em>

<em></em>Area_2 = 24in^2<em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em>Area = Area_1 - Area_2<em></em>

<em></em>Area = 96in^2 - 24in^2<em></em>

<em></em>Area = 72in^2<em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0
2 years ago
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