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2 years ago

11

YALL HELP PLEASE I WILL GIVE BRAINLIEST

1 answer:

vazorg [7]2 years ago

3 0

Solution:

<u>Note that:</u>

Triangle = 180°
5x + 130 + 3x + 2 = 180

<u>Simplify the equation to find x.</u>

5x + 130 + 3x + 2 = 180
=> 8x + 130 + 2 = 180
=> 8x + 2 = 180 - 130
=> 8x = 50 - 2
=> 8x = 48
=> x = 48/8 = 6

The value of x is 6.

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Write a word problem that can be described by the division expression 3÷1/4. Use complete sentences in your answer

AURORKA [14]

The question is simply asking us to create a word problem.
The word problem describing the division expression 3÷1/4 will be:
Given that Annie has 3 oranges and he wants to each orange into quarters, how many quarters will Annie have in total?

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3 years ago

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A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is:

$(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})$

$(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]$

$(x,y) = (10.452, 34.531)\,[km]$

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

$\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}$

$\theta \approx 16.840^{\circ}$

And the distance from the camp is calculated by the Pythagorean Theorem:

$r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}$

$r = 36.078\,km$

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

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3 years ago

What is the missing angle? Please provide an explanation.

irina [24]

Answer:

64 degrees

Step-by-step explanation:

Lets find the measure of the other angle in the other triangle with measures of 84 and 36.

Since there are 180 degrees in a triangle, we just add the other two angles and subtract from 180:

84 + 36 = 120

180 - 120 = 60

So the measure of the other angle in the other triangle is 60. Since there is a right angle we subtract 60 from 90

90 - 60 = 30

So the triangle with the missing angle has two angles with measures of 86 and 30. Now we add the measures and subtract from 180 again.

86 + 30 = 116

180 - 116 = 64

So the missing angle has a measure of 64 degrees

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gogolik [260]

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GREYUIT [131]

Answer:

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Here

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As Sampling Error is found by

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n= (z* s/ SE)²

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N= 28.9296= 28.93

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