Answer:
The expected number of times is 4.
Step-by-step explanation:
Looking at the question, we see that this follows a geometric distribution because it is asking for the expected number of trials hat will bring about the FIRST SUCCESS. The probability of success is
Since it is a geometric distribution, we know that the expected value of a random variable X, E(X) that follows a geometric distribution is given as:
E(X) = 1/p where p is the probability of success.
Therefore, the expected number of times will be
E(X) = 1/(1/p) = 1/(1/4) = 4.
Hence, the expected number of times is 4.
Answer:
r=d÷2 is the right answer
Answer: 11
Step-by-step explanation: First, 9 times 2 is 18. Then subtract 18-7 which equals 11.
First 3 terms are a^2 + n a^(n-)1 b + n(n-1)/2 * a^(n-2) b^2
So q^2 / pr = (n^2 * a^(2n-2) * b^2 ) / (1/2 * a^n * (n(n-1) * a^(n-2) * b^2 )
= n^2 * a^2n-2 * b^2
-----------------------------------
1/2 n(n-1) * a^(2n-2) * b^2
= 2n / n - 1 as required
given p = 4, q=32 and r = 96:-
32^2 / 4*96 = 2n / n-1
2n / n-1 = 8/3
6n = 8n - 8
2n = 8
n = 4 answer
Answer:
B
Step-by-step explanation:
i hope this helps :))