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MA_775_DIABLO [31]
3 years ago
9

Which statement is true about the function f(x) =

Mathematics
1 answer:
Andrei [34K]3 years ago
8 0
What are the options?
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sergeinik [125]
It’s f. my guy...........................

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HELP I NEED TO DO THIS BY TODAY
Fudgin [204]

Answer:

I can't see the picture.

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A curious patterns occurs in a group of people who all shake hands with one another. It turns out that you can predict the numbe
ycow [4]

Missing part of the question

Determine the number of handshakes, i, that will occur for each number of people, n, in a particular room. (people)

Answer:

S_n = \frac{n}{2}(n - 1)

Step-by-step explanation:

Given

For 5 people

\begin{array}{cc}{People} & {Handshakes} & {5} & {4} & {4} & {3} & {3} & {2} & {2} & {1} & {1} & {0} &{Total} & {10} \ \end{array}

Using the given instance of 5 people, the number of handshakes can be represented as:

(n - 1) + (n - 2) + (n - 3) + ........ + 3 + 2 + 1 + 0

The above sequence is an arithmetic sequence and the total number of handshakes is the sum of n terms of the sequence.

S_n = \frac{n}{2}{(T_1 + T_n})

Where

T_1 = n - 1 --- The first term

T_n = 0 --- The last term

So:

S_n = \frac{n}{2}(n - 1 + 0)

S_n = \frac{n}{2}(n - 1)

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali
Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}

rewrite the root

\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}

then cancel the terms that are cubes and bring them out of the root

\sqrt[3]{80}=2\sqrt[3]{10}

7 0
1 year ago
Twice c is greater than 28
OLEGan [10]

I think C would equal 15, because 14 + 14 = 28; 15 + 15 = 30 which is greater than 28.

6 0
2 years ago
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