Answer:
108 student tickets, and 176 adult tickets were sold
Step-by-step explanation:
Adult ticket $8 Call the number of adult tickets sold "a"
Student ticket $5 Call the number of student tickets sold "s"
Since we are talking about TWO consecutive days of sold out seats, the total number of seats sold were 2* 142 = 284
Then we create two different equations with the information given:
a + s = 284
8 * a + 5 * s = 1948
we can solve for s in the first equation as follows: s = 284 - a
and use it in the second equation
8 a + 5 (284 - a) = 1948
8 a + 1420 - 5 a = 1948
combining
3 a = 528
a = 528/3
a = 176
we find the number of student tickets using this answer in the substitution equation we used:
s - 284 - 176 = 108
Therefore 108 student tickets, and 176 adult tickets were sold.
Answer:
yes
Step-by-step explanation:
Answer:
-4
Step-by-step explanation:
f(x) = 4x - 12
Let x=2
f(2) = 4*2 - 12
= 8-12
= -4
Part A
The equation is b = 36*a or simply b = 36a
We take the size of the farm 'a' and multiply it by 36 to get the number of bushels of corn 'b'.
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Part B
The 36 means there are 36 times more bushels of corn compared to the size of the farm in acres
For example, if the size is 2 acres then
b = 36*a
b = 36*2
b = 72
yielding 72 bushels of corn
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Part C
Along the first row you should have: 25 and 30 in the missing blanks (over 900 and 1080 respectively)
You find this by dividing the value of b over 36
eg: b/36 = 900/36 = 25
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Then along the bottom row you should have the following for the blanks: 0, 360, 1800
These values are found by multiplying the 'a' value by 36
eg: if a = 10 then b = 36*a = 36*10 = 360
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Part D
Plot any two points you want from the table back in part C
So plot say (0,0) and (10,360). Then draw a straight line through those two points.
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Part E
The point (30,1080) means a = 30 and b = 1080
So if the farm is 30 acres, then it can produce 1080 bushels of corn
Notice how
b = 36*a
b = 36*30 <<-- replace 'a' with 30
b = 180
And how this matches up with the fourth column of the table in part C. So you can use this part to get a hint of how to fill out the table (or at least know what one column looks like)
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.