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Svet_ta [14]
3 years ago
11

What is ten minus one

Mathematics
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

9

Step-by-step explanation:

10 - 1 = 9

1, 2, 3, 4, 5, 6, 7, 8, 9, 10

if we erase 10, we have 9. Try that when subtracting 1 - any number

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The black line is the graph of y=x. Which of these equations could represent the blue line?
Solnce55 [7]

Here we can see that the blue line cuts exactly half way through the angle that the black line makes with x axis

That is all the x values are halved

Which implies all the x value of the black line are divided by 2 to form the points on the blue line

so that give us the function

y=\frac{1}{2} x

7 0
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What is 549 rounded to the nearest hundred
alukav5142 [94]

Answer:

550

Step-by-step explanation:

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What is the value of x in the diagram?
cestrela7 [59]

Answer:

x = 5

Step-by-step explanation:

x² + (2x+2)² = (2x+3)²

x² + 4x² + 8x + 4 = 4x² + 12x + 9

x² - 4x - 5 = 0

(x - 5)(x + 1) = 0

x = -1  This can be discounted as the answer because you cannot have a negative length

answer: x = 5

5 0
3 years ago
Need your help now please; the assignment is due tonight and this is the last problem I am having trouble with. The red box is t
Kobotan [32]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

here:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8)  from the graph, we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Therefore;

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

3 0
2 years ago
a candy bar box is in the shape of a triangular prism. The volume of the box is 1200 cubic centimetres. The base is 10 centimetr
Elina [12.6K]

Answer:

Step-by-step explanation:

V=\frac{HBL}{2}\\ \\ H=\frac{2V}{BL}\\ \\ H=\frac{2(1200)}{10(20)}\\ \\ H=12cm

7 0
3 years ago
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