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Leokris [45]
4 years ago
5

Graphically, a point is a solution to a system of two inequalities if and only if the point

Mathematics
2 answers:
trapecia [35]4 years ago
7 0

Answer:

Lies in the shaded regions of both the top and bottom inequalities.

Step-by-step explanation:

The point of solution for BOTH systems of inequalities must work for both equations. Therefore, the point has to lie in both top and bottom shaded regions or it won't work for both, but just one.

seropon [69]4 years ago
3 0

Answer:

C,lies in the shaded regions of both the top and bottom inequalities.

Step-by-step explanation:

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Can someone please help me answer this question. I dont know what to do.
pogonyaev

Answer:

7

Step-by-step explanation:

hi , you can see here we have a rectangle without a triangle :

area rectangle - area  triangle = area of the shape

Area of the triangle= L x l

=4 x 2

=8

Area of the triangle = \frac{b X h}{2}

=\frac{2 X 1}{2}

=1

So we do :   8 - 1 = 7

I hope it is gonna be helpful,

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Step-by-step explanation:

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3 years ago
Which is the graph of y – 3 = (x + 6)?
ivann1987 [24]

Answer:

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Step-by-step explanation:

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3 years ago
Suppose f(x) = = x. Find the graph of f(x - 2).
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5 0
3 years ago
Read 2 more answers
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
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