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Ber [7]
3 years ago
9

Fiona wrote the predicted and residual values for a data set using the line of best fit y=3.71x-8.85. Which statements are true

about the table? Select three options. The data point for x = 1 is above the line of best fit. The residual value for x = 3 should be a positive number because the data point is above the line of best fit. Fiona made a subtraction error when she computed the residual value for x = 4. The residual value for x = 2 should be a positive number because the given point is above the line of best fit. The residual value for x = 3 is negative because the given point is below the line of best fit.
Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

answer is 1, 4, 5 (just took the test, those are the answers)

Step-by-step explanation:

Vlad [161]3 years ago
3 0

Answer:

1,4 and 5

Step-by-step explanation:

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Can someone do #1 and #2 I don't really get the answer. My teacher hasn't explain anything. He just gave us the paper and we got
Elenna [48]
1) f(x) + g(x)

= 7√x + 4 + 2√x - 2

= √x(7 + 2) + 2

= 9√x + 2  [ Final Answer ]

2) f(x) - g(x)

= 7√x + 4 - (2√x - 2)

= 7√x + 4 - 2√x + 2

= √x(7 - 2) + 6

= 5√x + 6   [ Final Answer ]

Hope this helps!
5 0
3 years ago
Write 0.283, 28.5%, and — in order from least to greatest.
Inessa [10]

Answer:

28.5\% \: = 0.285(dividing \: by \: 100) \\ so \: its \: already \: written \: in \: order \\ 0.283 \: to \: 0.285

Good luck!

Intelligent Muslim,

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5 0
3 years ago
Natalia is writing a recursiye formula to represent the
Nadya [2.5K]

Answer:

1.5

Step-by-step explanation:

As the common difference is not same for all terms, the given sequence is a geometric sequence

the standard formula for a geometric sequence is:

a_n=a_1r^{n-1}

The formula to calculate common ratio is:

r =   \frac{a_n}{a_{n-1}}

Dividing the term by previous term

So,

r = 12/8 = 18/12 = 27/18 = 1.5

The value for common ratio will be:

1.5 ..

4 0
3 years ago
Read 2 more answers
If I start walking with 12 Oz of water and had 2 and 1 fourth left. How much did I drink?
ANTONII [103]
10 and 3/4 i think i may be wrong though hope it helps

8 0
3 years ago
A sample of 4 different calculators is randomly selected from a group containing 18 that are defective and 35 that have no defec
Sphinxa [80]
<span>1.

P(</span>at least one of the calculators is defective)= 

1- P(none of the selected calculators is defective).

2.

P(none of the selected calculators is defective)

           =n(ways of selecting 4 non-defective calculators)/n(total selections of 4)

3.

selecting 4 non-defective calculators can be done in C(35, 4) many ways, 

where  C(35, 4)= \frac{35!}{4!31!}= \frac{35*34*33*32*31!}{4!*31!}=  \frac{35*34*33*32}{4!}=  \frac{35*34*33*32}{4*3*2*1}=  52,360

while, the total number selections of 4 out of 18+35=53 calculators can be done in C(53, 4) many ways,

C(53, 4)= \frac{53!}{4!*49!}= \frac{53*52*51*50}{4*3*2*1}= 292,825

4. so, P(none of the selected calculators is defective)=\frac{52,360}{292,825} =0.18


5. P(at least one of the calculators is defective)= 

1- P(none of the selected calculators is defective)=1-0.18=0.82



Answer:0.82
7 0
3 years ago
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