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hodyreva [135]
2 years ago
11

Which expression is equivalent to (125^2/125^4/3)​

Mathematics
1 answer:
mariarad [96]2 years ago
6 0

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{125^2}{125^{\frac{4}{3}}}\implies \cfrac{(5^3)^2}{(5^3)^{\frac{4}{3}}}\implies \cfrac{5^{3\cdot 2}}{5^{3\cdot \frac{4}{3}}}\implies \cfrac{5^6}{5^4}\\\\\\ 5^6\cdot 5^{-4}\implies 5^{6-4}\implies 5^2\implies 25

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Lena walks 2.5km every day. How far does she walk in 7 days? Write your answer in meters.
Marat540 [252]

Answer:

17.5 meters

Step-by-step explanation:

To find how far she walks, multiply 2.5 by 7

2.5(7)

= 17.5

So, in 7 days, she walks 17.5 meters

6 0
3 years ago
If r = 4 and a6 = 192, what is the first term of the sequence?
blagie [28]

Answer:

Answer: Option c. 0.1875 is the first term of the sequence.

Step-by-step explanation:

In this question sixth term of a sequence is given as A(6)= 192

Ratio of terms is given as 4

And we have to calculate the first term of the sequence.

As per formula A(n) = A(1)×r^{n-1}

                         A(6) = A(1)(r)^{6-1}

                          192 = A(1)4^{5}

                           A(1) = \frac{192}{4^{5} }

                                 = 192/1024

                                 =0.1875

So the first term of the sequence will be 0.1875      



5 0
3 years ago
Translate the shape A three squares right and one square up
jonny [76]

To better give a visual, I drew it out instead.

The attachment is the solution.

8 0
1 year ago
Read 2 more answers
27. It costs $8.65 to ride the train. Ms. Reilly took
frozen [14]

Answer:$164.35

Step-by-step explanation:

You just multiply 19 × 8.65

6 0
3 years ago
What is the value of K?
Ksju [112]
Answer: The value of k for which one root of the quadratic equation kx2 - 14x + 8 = 0 is six times the other is k = 3.
Let's look into the solution step by step.

Explanation:

Given: A quadratic equation, kx2 - 14x + 8 = 0

Let the two zeros of the equation be α and β.

According to the given question, if one of the roots is α the other root will be 6α.

Thus, β = 6α

Hence, the two zeros are α and 6α.

We know that for a given quadratic equation ax2 + bx + c = 0

The sum of the zeros is expressed as,

α + β = - b / a

The product of the zeros is expressed as,

αβ = c / a

For the given quadratic equation kx2 - 14x + 8 = 0,

a = k, b = -14, c = 8

The sum of the zeros is:

α + 6α = 14 / k [Since the two zeros are α and 6α]

⇒ 7α = 14 / k

⇒ α = 2 / k --------------- (1)

The product of the zeros is:

⇒ α × 6α = 8 / k [Since the two zeros are α and 6α]

⇒ 6α 2 = 8 / k

⇒ 6 (2 / k)2 = 8 / k [From (1)]

⇒ 6 × (4 / k) = 8

⇒ k = 24 / 8

⇒ k = 3
6 0
2 years ago
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