The friction force exerted on the 2400kg car is 9408 Newtons
<h3>
What force will be exerted on the 2400kg car?</h3>
First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:
F = k*M
Where F is the force, M is the mass and k is the constant of proportionality.
We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:
6272N = k*1600kg
Solving for k we get:
k = (6272N)/(1600 kg) = 3.92 N/kg
Then the proportional relationship is:
F = (3.92 N/kg)*M
So if M = 2400kg, we have:
F = (3.92 N/kg)*2400kg = 9408 N
So the friction force exerted on the 2400kg car is 9408 Newtons
If you want to learn more about proportional realtions:
brainly.com/question/12242745
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Answer:
Step-by-step explanation:
If ' n ' is the cardinal number of a set, the number of subsets of a given set can be obtained by using the formula 2ⁿ
Given,
N = { 1 , 42 , 65 , 12 , 31 , 27 }
where n ( total number of elements ) = 6
So, the number of possible subsets of set N :
= 2ⁿ
= 2⁶
= 2 × 2 × 2 × 2 × 2 × 2
= 64
Hope I helped!
Best regards!!
The answer is 58 i hope this helped you and didn’t make you fail lol
Answer:
1 7/12
Step-by-step explanation:
6
5
+
4
3
2 Find the Least Common Denominator (LCD) of \frac{5}{6},\frac{3}{4}
6
5
,
4
3
. In other words, find the Least Common Multiple (LCM) of 6,46,4.
LCD = 1212
3 Make the denominators the same as the LCD.
\frac{5\times 2}{6\times 2}+\frac{3\times 3}{4\times 3}
6×2
5×2
+
4×3
3×3
4 Simplify. Denominators are now the same.
\frac{10}{12}+\frac{9}{12}
12
10
+
12
9
5 Join the denominators.
\frac{10+9}{12}
12
10+9
6 Simplify.
\frac{19}{12}
12
19
7 Convert to mixed fraction.
1\frac{7}{12}1
12
7
Answer:
Yes, i can help the answer is d.
Step-by-step explanation:
The pie chart shows the data of each amount and d. is the answer that will fill and divide by 2 with no remainder
