Help!! (sorry for bad quality) I have no idea how to do this

Steven has a rectangular rug with a perimeter of 16 feet. The width of the rug is 5 feet. What is the length of the rug?

boyakko [2]

$\boxed{\boxed{\text{Perimeter = 2(Length + Width)}}}$

Given that the perimeter is 16ft and width is 5 ft,
$16 = 2( Length + 5)$

Distribute 2:
$16 = 2Length + 10$

Take away 10 from both sides:
$2Length = 16 - 10$

Evaluate the right hand side:
$2Length = 6$

Divide by 2 on both sides:
$Length = 3$

$\boxed{\boxed{\text{Answer: Length = 3 ft}}}$

8 0

4 years ago

9x²+12xy+4y²???PLEASE HURRY 15 POINTS~

irakobra [83]

Answer:

(3x+2y)²

Step-by-step explanation:

sorry for typing tyy i thought it said free points :/

6 0

3 years ago

Read 2 more answers

Select all the parallelograms that have an area of 16 square units

Georgia [21]

Answer:it's c and b

Step-by-step explanation:

It's c an b

3 0

3 years ago

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SVEN [57.7K]

Answer:

$\boxed{\sf distance \: between \: the \: objects \: \: is \: 2.5 \: cm}$

Step-by-step explanation:

According to universal law of gravitation every object in the universe attracts every other particles that surrounds it with a force which is inversely proportional to the square of their distance of separation & directly proportional to

the product of their masses, given by standard formula.

$A = G \cdot \frac{m_1.m_2}{ {d}^{2} }$

where A,d & G are force of attraction, distance of separation & proportionality constant respectively.

Given:

A1 = 2 units

d1= 5 cm

A2 = 8 units

To find:

Distance of separation when the force of attraction is 8 units d2 = ?

Solution:

Substituting the given values in above at each point,

$A_1 = G \cdot \frac{m_1.m_2}{ {d_1}^{2} } \\ 2 = G \cdot \frac{m_1.m_2}{ {5}^{2} } \\ \sf similarly \: at \: second \: point \: of \: attraction \\ A_2 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ 8 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ \sf \: \: dividing \: both \: of \: the \: equation \\ \frac{2}{8} = \frac{G \cdot \frac{m_1.m_2}{ {5}^{2} }}{G \cdot \frac{m_1.m_2}{ {d_2}^{2} } } \\ \sf \: G \: m_1 and \: m_2 \: are \: \: constant \: hence \\ \sf they \: can \: be \: cancelled \: out \\ \frac{2}{8} = \frac{ \frac{1}{ {5}^{2} } }{ \frac{1}{ {d_2}^{2} } } \\ \sf rearranging \: above \: equation \\ \frac{1}{4} = \frac{{d_2}^{2} }{ {5}^{2} } \\ {d_2}^{2} = \frac{ {5}^{2} }{4 } \\ {d_2}^{2} = \frac{25}{4} \\ {d_2}^{2} = 6.25 \\ \sqrt{{d_2}^{2} } = \sqrt{6.25} \\ \boxed{ \sf{d_2} = 2.5 \: cm}$

Answer: the distance between the two objects is 2.5 cm, if the attraction between them is 8 units.

Learn more about universal law of gravitation here brainly.com/question/27244479

Thanks for joining brainly community!

7 0

2 years ago

Is 2/4 and 1/2 the same??

Reptile [31]

since 1/2 x 2/2 = 2/4

2/4 = 1/2

3 0

3 years ago