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3 years ago

Is it true that Confidence intervals are always close to their true population values?

Mathematics

1 answer:

user100 [1]3 years ago

6 0

Answer:

This means that there is a 95% probability that the confidence interval will contain the true population mean. Thus, P( [sample mean] - margin of error < μ < [sample mean] + margin of error) = 0.95.

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Consider the sequence below. What is the next terin in the sequence?

Lynna [10]

Answer:

jzjddndndndndhzzhxh

Step-by-step explanation:

hggahgababsbsj

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3 years ago

Which situation(s) could by modeled by a linear function?

liraira [26]

1 and 111 only would be your answer

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3 years ago

Read 2 more answers

Select all the equations where y=10y=10y, equal, 10 is a solution.

vekshin1

Answer:

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2 years ago

Solve using algebraic equation: 5sin2x=3cosx (No exponents)

DaniilM [7]

$5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x$

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

$10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0$

Now the zero product property tells us that there are two cases where this is true,

$\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}$

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of $\dfrac\pi2$ , so $x=\dfrac{(2n+1)\pi}2$ where $n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}$

which occurs twice in the interval $[0,2\pi)$ for $x=\arcsin\dfrac3{10}$ and $x=\pi-\arcsin\dfrac3{10}$ . More generally, if you think of $x$ as a point on the unit circle, this occurs whenever $x$ also completes a full revolution about the origin. This means for any integer $n$ , the general solution in this case would be $x=\arcsin\dfrac3{10}+2n\pi$ and $x=\pi-\arcsin\dfrac3{10}+2n\pi$ .

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3 years ago

The average fleet-wide performance of light duty trucks has made constant improvement since 1980. For example, the time for the

andrew11 [14]

A) T(m) = -0.16m +331.3

B) T(2015) = 8.9 . . . seconds

_____
The linear regression function of a graphing calculator can find the equation of the line easily. Or, you can use the 2-point form of the equation of a line.
.. T(m) = (10.5 -14.5)/(2005 -1980)*(m -1980) +14.5
.. T(m) = -0.16(m -1980) +14.5

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3 years ago