Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Ratio- 3: 2
3x + 2x = 150
5x = 150
x = 30
3x is the larger number so plug in the x value with 30.
3x
3 x 30
90
The larger number is 90.
Hope I helped.. ^^
Answer:
do you have pictures that I can see
Answer:
4
Step-by-step explanation:
3x-12=24
-12 to both sides
3x-12-12=24-12
3x=12
3x/3=12/3x
x=4
<span>0.888 = 888 / 1000
hope that helps</span>
