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Firlakuza [10]
2 years ago
8

What is the perimeter of ABC with vertices at A (-11,4) B(-7,8) and C (-4,4)

Mathematics
1 answer:
Alborosie2 years ago
3 0

Answer:

Step-by-step explanation:

Using the distance formula,

AB=\sqrt{(-11-(-7))^{2}+(4-8)^{2}}=\sqrt{16+16}=4\sqrt{2}\\AC=\sqrt{(-11-(-4))^{2}+(4-4)^{2}}=7\\BC=\sqrt{(-7-(-5))^{2}+(8-4)^{2}}=\sqrt{4+16}=2\sqrt{5}\\\\

So the perimeter is 4\sqrt{2}+7+2\sqrt{5}

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Answer:

\Huge\boxed{x=12}

Step-by-step explanation:

Hello There!

The following angles are complementary angles

Complementary angles have a sum of 90

So to solve for the variable (x) we use this equation

90 = 35 + 4x + 7

step 1 combine like terms

35+7=42

now we have

90 = 4x + 42

step 2 subtract 42 from each side

90 - 42 = 48

42 - 42 cancels out

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48 = 4x

step 3 divide each side by 4

4x/4 = x

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Answer:

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Step-by-step explanation:

<h3><em><u>Given</u></em><em><u>,</u></em></h3>
  • GRAM is a parallelogram
  • m<GMA = 66°
  • m<GRP = 32°
  • m<PAM = 41°
<h3><em><u>Solutions</u></em><em><u>:</u></em></h3>

i) <em>Since</em><em>,</em>

Angles on the same side of a transversal in a parallelogram, there sum is 180° so,

<RGM + <GMA = 180°

=> <RGM = 180° - <GMA

=> <RGM = 180° - 66°

=> <em><u><RGM = </u></em><em><u>114</u></em><em><u>°</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

ii) <em>Since</em><em>,</em>

Opposite angles of a diagonal as a transversal (here RM) are equal so,

<em><GRP = <PMA = 32°</em>

As we have <GMA = 66° so,

=> <GMP = <GMA - <PMA

= 66° - 32°

=> <em><u><</u></em><em><u>GMP</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>34</u></em><em><u>°</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

iii) <em>Since</em><em>,</em>

Opposite angles of a parallelogram are equal so,

<em><</em><em>RGM</em><em> = <</em><em>RAM</em><em> = </em><em>114</em><em>°</em>

As we have <PAM = 41° so,

=> <GAR = <RAM - <PAM

= 114° - 41°

=> <em><u><</u></em><em><u>GAR</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>73</u></em><em><u>°</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

iv) <em>Since</em><em>,</em>

We got <PMA = 32° and <PAM = 41°, so by angle sum property of a triangle PMA,

=> <MPA = 180° - 32° - 41°

=> <em><u><</u></em><em><u>MPA</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>107</u></em><em><u>°</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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