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Firlakuza [10]
2 years ago
8

What is the perimeter of ABC with vertices at A (-11,4) B(-7,8) and C (-4,4)

Mathematics
1 answer:
Alborosie2 years ago
3 0

Answer:

Step-by-step explanation:

Using the distance formula,

AB=\sqrt{(-11-(-7))^{2}+(4-8)^{2}}=\sqrt{16+16}=4\sqrt{2}\\AC=\sqrt{(-11-(-4))^{2}+(4-4)^{2}}=7\\BC=\sqrt{(-7-(-5))^{2}+(8-4)^{2}}=\sqrt{4+16}=2\sqrt{5}\\\\

So the perimeter is 4\sqrt{2}+7+2\sqrt{5}

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What is another way to write the absolute value inequality |p| less than or equal to 12
const2013 [10]

Since it is written like this: |p| ≤ 12, you can subtract 12 from both sides using the subtraction property of equality to obtain your answer:

|p|-12≤0

Hope this helps!

4 0
3 years ago
Read 2 more answers
(1-w-w²)⁶=64 prove thta​
VLD [36.1K]

1−w−w2=64

Step 1: Simplify both sides of the equation.

−w2−w+1=64

Step 2: Subtract 64 from both sides.

−w2−w+1−64=64−64

−w2−w−63=0

For this equation: a=-1, b=-1, c=-63

−1w2+−1w+−63=0

Step 3: Use quadratic formula with a=-1, b=-1, c=-63.

w= −b±√b2−4ac /2a

w= −(−1)±√(−1)2−4(−1)(−63) /2(−1)

w= 1±√−251/ −2

7 0
2 years ago
How to find the side of a rhombus with given diagonals?
spayn [35]
The diagonals of a rhombus are perpendicular bisectors of each other. You can use the Pythagorean theorem. If the diagonals are length "a" and "b", the side length of the rhombus (s) is
  s = (1/2)√(a²+b²)
7 0
3 years ago
Add 2x4 - 6x3 + 5x to the difference between 9x3 + 8x2 - 2 and 4x4 - 2x2 + 8x - 5.
DedPeter [7]

Simplify (x3 +  3x2 + 5x – 4) –  (3x3 – 8x2 – 5x + 6)

The first thing I have to do is take that "minus" sign through the parentheses containing the second polynomial. Some students find it helpful to put a "1" in front of the parentheses, to help them keep track of the minus sign.

Here's what the subtraction looks like, when working horizontally:

(x3 + 3x2 + 5x – 4) – (3x3 – 8x2 – 5x + 6)

(x3 + 3x2 + 5x – 4) – 1(3x3 – 8x2 – 5x + 6)

(x3 + 3x2 + 5x – 4) – 1(3x3) – 1 (–8x2) – 1(–5x) – 1(6)

x3 + 3x2 + 5x – 4 – 3x3 + 8x2 + 5x – 6

x3 – 3x3 + 3x2 + 8x2 + 5x + 5x – 4 – 6

–2x3 + 11x2 + 10x –10

And here's what the subtraction looks like, when going vertically:

x

3

−(3x

3

​

 

+3x

2

−8x

2

​

 

+5x

−5x

​

 

−4

+6)

​

​

In the horizontal addition (above), you may have noticed that running the negative through the parentheses changed the sign on each and every term inside those parentheses. The shortcut when working vertically is to not bother writing in the subtaction sign or the parentheses; instead, write the second polynomial in the second row, and then just flip all the signs in that row, "plus" to "minus" and "minus" to "plus".

\

x

3

–3x

3

−2x

3

​

 

+3x

2

+8x

2

+11x

2

​

 

+5x

+5x

+10x

​

 

−4

–6

−10

​

​

Either way, I get the answer:

–2x3 + 11x2 + 10x – 10

4 0
3 years ago
What is the sum of (2x4 + 5x3 - 8x2 - x + 10) and (8x4 - 4x3 + x2 - x + 2)?
balu736 [363]

Option D: 10x^4+x^3-7x^2-2x+12 is the right answer

Step-by-step explanation:

Given polynomials are:

P_1 : 2x^4+5x^3-8x^2-x+10\\P_2: 8x^4-4x^3+x^2-x+2

We have to find the sum of polynomials

So,

S = P_1+P_2\\= (2x^4+5x^3-8x^2-x+10) + (8x^4-4x^3+x^2-x+2)\\=2x^4+5x^3-8x^2-x+10+8x^4-4x^3+x^2-x+2\\

Combining like terms

=2x^2+8x^4+5x^2-4x^3-8x^2+x^2-x-x+10+2\\= 10x^4+x^3-7x^2-2x+12

Hence,

Option D: 10x^4+x^3-7x^2-2x+12 is the right answer

Keywords: Polynomials, sum

Learn more about polynomials at:

  • brainly.com/question/2116906
  • brainly.com/question/2131336

#LearnwithBrainly

3 0
3 years ago
Read 2 more answers
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