Question

What is the perimeter of ABC with vertices at A (-11,4) B(-7,8) and C (-4,4)

Answer 1

Answer:

Step-by-step explanation:

Using the distance formula,

$AB=\sqrt{(-11-(-7))^{2}+(4-8)^{2}}=\sqrt{16+16}=4\sqrt{2}\\AC=\sqrt{(-11-(-4))^{2}+(4-4)^{2}}=7\\BC=\sqrt{(-7-(-5))^{2}+(8-4)^{2}}=\sqrt{4+16}=2\sqrt{5}$

So the perimeter is $4\sqrt{2}+7+2\sqrt{5}$