Africa has started exporting products that are not common in their country. These are vegetables and fruits which do not normally grow in Africa. The country has started exporting fruits and vegetables like snow peas, globe artichoke, Brussel sprout, passion fruit and pineapples to the European Nation. They were able to get money from this because these products have very high value in these countries.
Answer:
$137.50 per unit
Explanation:
The computation of the total indirect manufacturing cost per unit is shown below:
Machine setups 15000 ÷ 100 × 25 = $3750
Material moves 22500 ÷ 225 × 40 = $4000
M/c. Operations 14000 ÷ 175 × 75 = $6000
Total Cost for 100 units $13,750
And since there is 100 units
So, the total indirect manufcturing cost per unit is
= $13,750 ÷100 units
= $137.50
<em />I think it is C but don't quote me on it.
Answer:
Full question: <em>On their birthdays, employees at a large company are permitted to take a 60-minute lunch break instead of the usual 30 minutes. Data were obtained from 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday. The company wishes to investigate whether these data provide convincing evidence that the mean time is greater than 60 minutes. Of the following, which information would NOT be expected to be a part of the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance?</em>
<em>Answe</em><em>r: Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
Explanation:
<em>From the given question let us recall the following statements:</em>
<em>Employees at a large company are permitted to take a 60-minute Lunch break instead of the 30 minutes.</em>
<em>Data was gotten from = 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday</em>
<em>Given that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes.</em>
<em>The company tries to investigate the data to know that the mean is greater than 60 minutes</em>
<em>the next step is to find the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance</em>
<em>Therefore,</em>
<em>Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
<em>Or</em>
<em>The P-value> 0.05</em>
<em>The mean time is not greater than 60 minutes</em>
