The required expression is 100 - 0.2w
Step-by-step explanation:
Given,
Amount of radioactive substance = 100 mg
The substance decreases by 20% each week.
To find the remaining amount of the in w weeks.
Now,
Each week 20% = 0.2 of the substance will be decreased.
So, in w weeks 0.2×w of the the substance will be decreased.
Hence,
The remaining substance = 100 - 0.2w
Answer:
Step-by-step explanation:
a.
y=0.75x
y-y1=(y2-y1)/(x2-x1)×(x-x1)
y-3=(6-3)/(8-4) (x-4)
y-3=3/4(x-4)
y-3=3/4 x-3
y=3/4 x-3+3
y=3/4 x
if y=f(x)
f(x)=0.75x
c.
f(12)=0.75×12=9$
First, you try to make sure that both the denominators are the same. In order to do this, you multiply both fractions' numerator and denominator by the other fraction's denominator. Next, you combine like terms in the numerator, and then you simplify the fraction.
Im pretty sure it’s C. 9 times longer
Answer:
1.47
Step-by-step explanation:
it will be 1.47 for three pounds
