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4 years ago

7

the distance from a star to a planet is approximately 98,000,000 miles. if the light travels at a rate of 186,000 miles per seco

nd, how long does it take light from the star to reach this planet?

1 answer:

nadya68 [22]4 years ago

3 0

It will take 526.8817.... seconds for the light to reach the planet.

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A 2013 study by pediatrician investigates whether it in better to give children the diphtheria, tetanus and pertussis (DTaP) vac

jonny [76]

Answer:

A

Step-by-step explanation:

Since chi-squared calculated value is greater than p-value, there is a relationship between vaccine location and severe reaction.

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3 years ago

Read 2 more answers

380% of what is 99? (Round to the nearest whole number)

scoray [572]

Answer:

26

Step-by-step explanation:

<u>Let the number be x</u>

380% of x is 99
x*3.8 = 99
x = 99/3.8
x = 26 rounded to the nearest whole number

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3 years ago

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If DEF and MNO are two triangles such that DE=MN and EF=NO, which of the following would be sufficient to prove that triangles a

Delvig [45]

Answer:

D. ∠E ≅ ∠N

Step-by-step explanation:

The pair of sides meet at vertex E in ∆DEF and at vertex N in ∆MNO. Since the sides that make up angles E and N are shown congruent, it is sufficient to show ...

∠E ≅ ∠N

Then the SAS congruence postulate can be claimed.

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<em>Additional comment</em>

The alternative is to show DF ≅ MO. That would allow you to claim SSS congruence. That is not an answer choice.

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3 years ago

Based on lines 63-67 ("nobody . . . sheep"), the author

serious [3.7K]

(C) "having a deep fondness for border collies and therefore overestimating them"

While acknowledging that "dogs may be noble, charming, loyal, and dependable," the author of Passage 1 speculates that they might not have "earned those extra intellect points." In contrast, the author's admiration for dogs may lead one to believe that the depiction of "pure intelligence shining in the face of a border collie" in lines 63–67 is exaggerated.

The answer is not (A). Passage 1's author would probably assume that Passage 2's author has a strong emotional bond with dogs. (B) is the wrong answer. The subjective assessment of canine intellect is shown in lines 63–67. They don't imply that the author of Passage 2 has in-depth understanding of the relevant studies.

The answer is not (D). Despite the fact that the author of Passage 2 appears to prefer personal experience over the findings of scientific investigations, lines 63–67 do not demonstrate any scorn for "traditional" research. The answer is not (E).

It would be harsh to assert that the author of Passage 2 has a limited understanding "of what constitutes intelligence" despite the fact that the two authors may hold different opinions on the degree to which dogs are able to reason.

Here's another question with an answer similar to this about dogs:

brainly.com/question/18951741

#SPJ4

5 0

2 years ago

Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a rand

SOVA2 [1]

Answer:

<u>Question 1:</u>

<u>(a) </u>P(x<60) = 0.9236

<u>(b) </u>P(x>16) = 0.9564

<u>(c) </u>P(16<x<60) = 0.88

<u>(d) </u>P (x>60) = 0.0764

<u />

<u>Question 2:</u>

<u>(a) </u>P(x<3) = 0.0668

<u>(b) </u>P(x>7) = 0.0062

<u>(c) </u>P(3<x<7) = 0.927

<u />

Step-by-step explanation:

<u>Question 1:</u>

x = no. of mg of porphyrin per deciliter of blood.

μ = 40

σ = 14

(a) We need to compute P(x<60). We need to find the z-score using the normal distribution formula:

z = (x - μ)/σ

P(x<60) = P((x - μ)/σ < (60 - 40)/14)

= P(z < 20/14)

= P(z<1.43)

Using the normal distribution probability table we can find the value of p at z=1.43.

P(z<1.43) = 0.9236

so, P(x<60) = 0.9236

(b) P(x>16) = P(z>(16-40)/14)

= P(z>-1.71)

= 1 - P(z<-1.71)

= 1 - 0.0436

P(x>16) = 0.9564

(c) P(16<x<60) = P((16-40)/14) < x < (60-40)/14)

= P(-1.71 < z < 1.43)

This probability can be calculated as: P(z<1.43) - P(z<-1.71)

P(16<x<60) = 0.9236 - 0.0436

P(16<x<60) = 0.88

(d) P(x>60) = 1 - P(x<60)

we have calculated P(x<60) in part (a) so,

P(x>60) = 1 - 0.9236

P (x>60) = 0.0764

<u>Question 2:</u>

μ = 4.5 mm

σ = 1.0 mm

In this question, we will again compute the z-scores and then find the probability from the normal distribution table.

(a) P(x<3) = P(z<(3-4.5)/1)

= P(z<-1.5)

P(x<3) = 0.0668

(b) P(x>7) = 1 - P(x<7)

= 1 - P(z<(7-4.5)/1)

= 1 - P(z<2.5)

= 1 - 0.9938

P(x>7) = 0.0062

(c) P(3<x<7) = P(x<7) - P(x<3)

we have computed both of these probabilities in parts (a) and (b) so,

P(3<x<7) = 0.9938 - 0.0668

P(3<x<7) = 0.927

6 0

3 years ago