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Gnom [1K]
3 years ago
8

The sum of a rational number and a irrational number is _____ rational

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
5 0

Answer:

never

Step-by-step explanation:

maria [59]3 years ago
5 0

Answer:

I'm glad you asked!

Step-by-step explanation:

The answer is never.A rational number and a irritation number will never ever be rational.

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Joyce saved $120 on an item that was $75 off. What was the original price
vaieri [72.5K]

The original price of the item will be $ 480.When there is 75% off on the original price.

<h3>What is the percentage?</h3>

The quantity of anything is stated as though it were a fraction of a hundred. A fraction of 100 can be used to express the ratio.

The right question is

"Joyce saved $120 on an item that was 75 %  off. What was the original price?"

Given data;

% off = 75

Amount saved $120

Let the original price of the item is x

75 % of x + $120 = x

0.75x+ 120 =x

0.25 x =120

x=120/0.25

x=480

Hence, the original price of the item will be $ 480.

To learn more about percentages, refer to:

brainly.com/question/13450942

#SPJ1

5 0
2 years ago
Is the relation { (5, 2), (-1, 6), (8, -2), (5, 3)} a function? why or why not? list the domain and range
Tasya [4]

Answer:

it is not a function because the input 5 (x) has more than one output (y)

domain (5,-1,8)

range (2,6,-2,3)

Step-by-step explanation:

5 0
3 years ago
What is 75 minutes to ten hours in ratio and simplest form
Arada [10]

Answer:

1:8

Step-by-step explanation:

75min/10hr

10*60=600

75/600

1/8


7 0
3 years ago
Your question here (keep it simple and clear to get the best answer)
ZanzabumX [31]

What is the largest organ in your body?


7 0
3 years ago
If tan A = 4/3 and sin B = 45/53 and angles A and B are in Quadrant I, find the value of tan(A+B)
lbvjy [14]

Answer:

First, find tan A and tan B.

cosA=35 --> sin2A=1−925=1625 --> cosA=±45

cosA=45 because A is in Quadrant I

tanA=sinAcosA=(45)(53)=43.

sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.

sinB=1213 because B is in Quadrant I

tanB=sinBcosB=(513)(1312)=512

Apply the trig identity:

tan(A−B)=tanA−tanB1−tanA.tanB

tanA−tanB=43−512=1112

(1−tanA.tanB)=1−2036=1636=49

tan(A−B)=(1112)(94)=3316

kamina op bolte

✌ ✌ ✌ ✌

3 0
2 years ago
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