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1 year ago

Which set of ordered pairs could be generated by an exponential function?

Mathematics

1 answer:

Ede4ka [16]1 year ago

6 0

Answer:

(1,1), (2, 1/4), (3, 1/9), (4, 1/16)

Step-by-step explanation:

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Evaluate the following numerical expressions. 6+2^3•3

Stolb23 [73]

The answer is 30
6+8•3
6+24 =30

7 0

2 years ago

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Plz someone help I will mark brainlest diameter is 8.8 yd

sweet [91]

Answer:

60.79 square yards.

Step-by-step explanation:

d = 2r; d = 8.8.

8.8 = 2r

r = 8.8 / 2

r = 4.4 yards.

Since we now have the radius, we can find the area of the circle, which can be found using πr^2, or 3.14 * r^2.

4.4^2 * 3.14 = 19.36 * 3.14 = 60.7904.

Since the question tells us to round to the nearest hundredth, our final answer will be 60.79 square yards.

Hope this helps!

5 0

2 years ago

Find the unit rate. Round to the nearest hundredth, if necessary.

nekit [7.7K]

Answer:

Usually, I would divide 300 and 17 to get my answer

Step-by-step explanation:

5 0

2 years ago

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Identify the standard form of a circle equation x^2+2x+y^2-2y=2

Bas_tet [7]

Answer:

The standard from of the expression is: $(x +1)^2 + (y-1)^2 = (2)^2$

Step-by-step explanation:

Here the given expression is :

$x^2+2x+y^2-2y=2$

Now, the standard form of a circle is given as :

$(x-h)^2 + (y -k)^2 = r^2$

Here, (h,k) = Coordinates of Center, r = Radius

Also, use the algebraic identity:

$(a \pm b)^2 = a^2 + b^2 \pm 2ab\\$

Now, converting the given expression in the standard form, we get:

$x^2+2x+y^2-2y=2$

Add 2 on both sides of the equation, we get:

$x^2+2x+y^2-2y +2=2 + 2\\\implies x^2+2x + 1 + y^2-2y + 1 = 4\\\implies (x^2+2x + 1 )+ (y^2-2y + 1) = 4\\\implies (x +1)^2 + (y-1)^2 = (2)^2$

So, here the standard from of the expression is:

$(x +1)^2 + (y-1)^2 = (2)^2$

Center coordinates here are (h,k) = ( -1 ,1) and Radius = 2 units

4 0

3 years ago

Can y’all help me I don’t understand this bc I didn’t pay attention when we learned this..?

Alborosie

Answer: the answer is c

Step-by-step explanation:

7 0

2 years ago

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