Answer:
Step-by-step explanation:
The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.
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<h3>Given relation</h3>
Let x represent the width of the shed. Then the length is (2x+3), and the area is ...
A = LW
20 = (2x+3)(x) . . . . . area of the shed
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<h3>Solution</h3>
Completing the square gives ...
2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides
2(x +0.75)² = 21.125 . . . . . . . write as a square
x +0.75 = √10.5625 . . . . . divide by 2, take the square root
x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution
The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.
Answer:
It depends on how many inches they are from the finish line.
Step-by-step explanation:
However, they will be at the same distance at 90 inches when Glenda hops 5 times. 18 x 5 = 90. Penny will also make it to 90 inches when she hops 6 times. 15 x 6 = 90. Then, you will subtract 90 inches from how long the race is in inches.
Hope this helps!
Well what’s the base and what’s the height and then times then
Answer:
Step-by-step explanation:
Circumference = 2πr
Let's set the equation equal to the formula:
16 = 2πr
16/2 = πr
8 = πr
r = 8/π
Dear user,
3 × 8000283743729 = 2.4000851
