Answer: The sailboat is at a distance of 15 km from the port.
Step-by-step explanation: Given that a sail boat leaves port and sails 12 kilometers west and then 9 kilometers north.
We are to find the distance between the sailboat from the port in kilometers.
Since the directions west and north are at right-angles, we can visualize the movement of the sailboat in the form of a right-angled triangle as shown in the attached figure.
The sailboat moves leaves the port at P and reach O after sailing 12 km west. From point O, again it moves towards north 9 km and reach the point S.
PS = ?
Using the Pythagoras theorem, we have from right-angled triangle SOP,
Thus, the sailboat is at a distance of 15 km from the port.
=1/2
you add both on each side then subtract 2 from you anser
We will use the formula for the slope:
m = ( y2- y1 ) / ( x2 - x1 )
For PQ : m = ( 0 - 0 ) / ( a + c - 0 ) = 0
For RS : m = ( b - b ) / ( a - ( 2a + c )) = 0
Both slopes are m = 0, so PQ and RS are parallel to x - axis and at the same time parallel to each other ( PQ | | RS ). One pair of opposite sides is parallel.
Area of a triangle = (height * base ) / 2
height = (Area * 2) / base
height = (49.5 * 2) / 9
height = 99 / 9
height = 10 cm²