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Yuki888 [10]
3 years ago
15

PLease hurry! i need it! And the testing thing is happening, so before 6 pm?

Mathematics
1 answer:
ololo11 [35]3 years ago
8 0

\begin{cases} -x+3y=9\\\\ y=\cfrac{2}{3}x \end{cases} \\\\[-0.35em] ~\dotfill\\\\ -x+3y=9\implies 3y=9+x\implies \underline{3y-9=x} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting ont the 2nd equation}}{y=\cfrac{2}{3}(\underline{3y-9})\implies 3y=2(3y-9)}\implies 3y=6y-18\implies 18+3y=6y \\\\\\ 18=3y\implies \cfrac{18}{3}=y\implies \boxed{6=y}

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y=2/3x+4.3

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8

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4 0
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What’s.the perimeter of a square with an area of 49 cm2
Free_Kalibri [48]

Answer:

<h3>28</h3>

Step-by-step explanation:

Area of a square =

s^2

Perimeter =

4\times s

Where s = side

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8 0
3 years ago
The San Andreas fault separates the pacific plates from the North America plate. The pacific plate moved northward relative to t
lesantik [10]

Answer:

The time, t it will take LA and San Francisco to be next to each other is 8,245,614.04 years which is over 8 million years

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The given parameters are;

The speed with which the pacific plate moved northward relative to the North American plate = 5.7 cm/year = 5.7 × 10⁻⁵ km/year

The distance between current LA and San Francisco = 470 km

From the formula for speed, s, we have

Speed = Distance/Time

Therefore, Time, t = Distance/Speed

The time, t it will take LA and San Francisco to be next to each other is given as follows;

t = (Distance between LA and San Francisco)/(The speed with which the pacific plate)

t = (470 km)/(5.7 cm/year) = 470/(5.7 × 10⁽⁻⁵⁾) = 8245614.04 years

Therefore, the time, t it will take LA and San Francisco to be next to each other is 8245614.04 years.

6 0
3 years ago
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