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3 years ago

EMERGENCY (NEED HEP NOW!!!)

Mathematics

1 answer:

diamong [38]3 years ago

8 0

Answer:

x=-2.25,y=-2.25

Step-by-step explanation:

The given system is

$4x - y = - 9 \\ 3x - 3y = 0$

We want to solve the system for x and y that makes the system true.

Let us multiply the first equation by 3 while maintaining the second equation:

$12x -3 y = - 27 \\ 3x - 3y = 0$

Subtract the current second equation from the first one.

$12x = - 27$

Divide through by 12:

$x = - \frac{27}{12} = - 2.25$

From the second equation we have:

$3x = 3y$

This implies that:

$x = y = - 2.25$

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Nathan is buying a cell phone for his business. The regular price of the cell phone is $ 179. If he buys the cell phone in the n

shutvik [7]

Answer:

The sale price will be 143.20

Step-by-step explanation:

20% of 179 is 35.80

179 - 35.80 = 143.20

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2 years ago

Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the

adoni [48]

Answer:

45.55 meters

Step-by-step explanation:

I'm guessing she recorded above her height, right?

To find the height of the dam, use the tangent ratio:

$tangentX=\frac{opposite}{adjacent}$

The height of the dam is the side opposite the given angle, and this will represent x. The adjacent side (the hypotenuse is NEVER considered the adjacent side) is the distance from Scarlett to the dam. The angle of elevation is the angle of 26°. Insert the values:

$tan26=\frac{x}{90}$

Solve for x. Multiply both sides by 90:

$90*(tan26)=90*(\frac{x}{90})\\\\90*tan26=x$

Insert equation into a calculator:

$x=90*tan26\\\\x=43.9$

Now add Scarlett's height:

$43.9+1.65=45.55$

The dam is 45.55 meters tall.

Finito :D

6 0

3 years ago

The Sun is roughly 10^2 times as wide as the Earth. The Star KW Sagittarii is roughly 10^5 times as wide as the Earth. About how

Studentka2010 [4]

Answer:

1000 times

Step-by-step explanation:

Given:

The Sun is roughly 10^2 times as wide as the Earth.

The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.

Question asked:

About how many times as wide as the Sun is KW Sagittarii?

Solution:

Let the width of the earth = $x$

As the Sun is roughly 10^2 times as wide as the Earth, hence the width of the sun = $x\times10^{2}$

And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star = $x\times10^{5}$

Now, to find that how many times width of the Star KW Sagittarii is as respect to the width of the Sun, we will simply divide:

Width of the Star KW Sagittarii = $x\times10^{5}$

Width of the Sun = $x\times10^{2}$

$\frac{x\times10^{5} }{x\times10^{2} }$

x canceled by x

$\frac{10^{5} }{10^{2} } =10^{5-2} =10^{3} =10\times\ 10\times10=1000$

Therefore, Star KW Sagittarii is 1000 times wider than Sun.

First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.

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3 years ago

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EastWind [94]

Answer:

Step-by-step explanation:

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3 years ago

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