3 years ago

Can you help me please

Mathematics

1 answer:

Elena L [17]3 years ago

4 0

Answer:

this is the ans

Step-by-step explanation:

hope it helps!!!

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Mark deposited $9,000 into two saving accounts bearing simple interest. One of the accounts has an interest rate of 8% while the

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0.07x+0.08 (9000-x)=700
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-0.01x=-20
X=20÷0.01
X=2,000 invested at 7%

9000-2000=7000 invested at 8%

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100 points! Solve the equation identify any extraneous solutions.

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A = √7 + √c and b = √63 + √d where c and d are positive integers.

mrs_skeptik [129]

Answer:

$\displaystyle a:b=\frac{1}{3}$

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

$a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]$

$b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]$

$\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]$

From [3]:

$9c=d$

Replacing into [2]:

$b=\sqrt{63}+\sqrt{9c}$

We can express 63=9*7:

$b=\sqrt{9*7}+\sqrt{9c}$

Taking the square root of 9:

$b=3\sqrt{7}+3\sqrt{c}$

Factoring:

$b=3(\sqrt{7}+\sqrt{c})$

Find the ration a:b:

$\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}$

Simplifying:

$\boxed{a:b=\frac{1}{3}}$

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