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gtnhenbr [62]
3 years ago
10

How do you solve fraction equations ?​

Mathematics
1 answer:
user100 [1]3 years ago
6 0

Answer:

y=2.

Step-by-step explanation:

What you need to do is cross multiplication. So it will be 9(4-2y)=-3(3y-6).

You will then distribute the -3 and the 9 into the equation to get 36-18y=-9y+18.

You will then add the y's together to get -9y+36=18.

You will then subtract the 18 from both sides to get -9y=-18.

y=2 is your answer.

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Angle AED is 109 degrees.  

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3 years ago
What is the most efficient way to solve the equation?<br> 5j = 40
Maru [420]

Answer: j = 8

Step-by-step explanation: To solve for <em>j</em> in this equation, we want to get <em>j</em> by itself on the left side of the equation. Since <em>j</em> is being multiplied by 5, to get <em>j</em> by itself, we need to divide by 5 on the left side of the equation. Since we divided by 5 on the left side, we must also divide by 5 on the right side.

On the left side, notice that the 5's cancel out so we are simply left with <em>j</em>. On the right side, we have 40 divided by 5 which gives us 8 so we have j = 8.

Finally, remember to check your answer by substituting an 8 back into the original equation. So we have 5 (8) = 40 which is a true statement so our answer checks. Remember to show all your work when solving equations.

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3 years ago
Read 2 more answers
Solve this rational equation ​
tino4ka555 [31]

Answer:

<h2>x = -1</h2>

Step-by-step explanation:

\text{Domain:}\\\\x-4\neq0\ \wedge\ x-2\neq0\ \wedge\ x^2-6x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x^2-4x-2x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x(x-4)-2(x-4)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ (x-4)(x-2)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x-4\neq0\ \wedge\ x-2\neq0\\\\\boxed{D:x\neq4\ \wedge\ x\neq2}

\dfrac{1}{x-4}+\dfrac{x}{x-2}=\dfrac{2}{x^2-6x+8}\\\\\dfrac{1(x-2)}{(x-4)(x-2)}+\dfrac{x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\\\\\dfrac{x-2+x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\iff x-2+x(x-4)=2\\\\x-2+(x)(x)+(x)(-4)=2\\\\x-2+x^2-4x=2\qquad\text{subtract 2 from both sides}\\\\x^2-3x-4=0\\\\x^2-4x+x-4=0\\\\x(x-4)+1(x-4)=0\\\\(x-4)(x+1)=0\iff x-4=0\ \wedge\ x+1=0\\\\x-4=0\qquad\text{add 4 to both sides}\\x=4\notin D\\\\x+1=0\qquad\text{subtract 1 from both sides}\\x=-1\in D

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Step-by-step explanation:

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