Equation for n-th term of geometric sequence:
a(n)=a(1)*r^(n-1)
For 4th term,
a(4)=a(1)r^(4-1)
1/2=4*r^3
∛(1/8) = ∛(r^3)
r=1/2
For 10th term,
a(n)=a(1)*r^(n-1)
a(10)=4*(1/2)^(10-1)
a(10) =4/(2^9) =( 2^2)/(2^9)= 1/(2^7) = 1/128
Set up the composite function and evaluate
fg (x^2)=gx^4
Answer:
12
Step-by-step explanation:
is you multiply 4/4 times 12 you will get 12! :)
Hope this helps!
So hmmm notice the picture below
get the area of the "square" that contains both triangles
and then subtract the area of that gray triangle
notice the base of the triangle, is just 14, the height is 14
the difference, is the area other two blue smaller triangles