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USPshnik [31]
3 years ago
11

Find the slope of the line that passes through (4, 11) and (8, 10).

Mathematics
1 answer:
Svetllana [295]3 years ago
3 0
-1/4 is the answer to your question
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7× - 7;×=4<br>helpppppp​
Flura [38]

Answer:

7(4)-7

28-7

21

Step-by-step explanation:

6 0
3 years ago
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Quick question, is this the same as this???
salantis [7]
Your first steps are correct.  Mult. the given fraction by (1+sqrt(5)) / (1+sqrt(5)).

Result:  8(1 + sqrt(5) )       8(1 + sqrt(5) )
             ------------------- = ----------------------
                 1 - 5                         -4

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8 0
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What is x^4+25 factored
OLga [1]

(x^2+5)(x^2-5)

I hope this helps :)

3 0
3 years ago
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A florist sold bouquets of red roses to 15 of the first 20 customers who came into his shop. What is the experimental probabilit
Oksanka [162]
In fraction that would be 3/4 because 15/20 simplified would be three quarters. 
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7 0
3 years ago
The rate at which a quantity of a radioactive substance decays is proportional to the quantity of the substance. The constant of
Butoxors [25]

Answer:

\frac{dN}{dt} = λN           N(0) = 6

N(t) = N₀e^(λt)

Applying the inital value condition

N(t) = 6e^(λt)

Step-by-step explanation:

Summarizing  the information briefly and stating the  variables in the problem.

t = time elapsed during the decay

N(t) = the amount of the radioactive substance remaining after time t

λ= The constant of proportionality  is called the decay constant or decay rate

Given the initial conditions

N(0) = N₀ = 6

The rate at which a quantity of a radioactive substance decays (\frac{dN}{dt}) is proportional to the quantity of the substance (N)  and λ is the constant of proportionality  is called the decay constant or decay rate :

\frac{dN}{dt} = λN          

N(t) = N₀e^(λt) ......equ 1

substituting the value of  N₀ = 6 into equation 1

N(t) = 6e^(λt)

3 0
3 years ago
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