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wolverine [178]

3 years ago

12

Find the value of the expressions below for X=10 X whith the 2ed power -2(X+5)

1 answer:

Elena-2011 [213]3 years ago

8 0

The answer is -30.

Why: If x = 10, then you fill in -2(10 + 5). Do -2 times 10 and -2 times 5. The new equations is (-20 + -10). When you add two negatives, the answer will be a negative so the answer is -30.

Hope this helps, if you need any further help or questions on this, message me! :)

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The surface area of a sphere is S(x) = 4πx2, where x is the length of the radius of the sphere. Restrict the domain to create a

Orlov [11]

Given that the surface area of the sphere is S(x)=4πx², the inverse function will be obtain as follows: make x the subject of the function
S(x)/(4π)=x²
get the square root of both sides:
x=√[S(x)/(4π)]
replace x by S⁻¹(x) and S(x) by x
this will give us the inverse as :
S⁻¹(x)=√[x/(4π)]
The above implies that the inverse is the square root of the radius divided by 4π

8 0

4 years ago

What is 2.068 rounded to the nearest 0.1

Lilit [14]

Answer:

2.1

Step-by-step explanation:

7 0

3 years ago

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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

The quotient of two and a number, subtracted from 17

Vilka [71]

The quotient means divide

17 - (2/n) <== ur expression

4 0

3 years ago

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Please help me!!!!!!

Gwar [14]

I hope this helps!
Can I please have brainiest?

4 0

3 years ago