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Tpy6a [65]
3 years ago
11

Find the value of the combination. 16c14 HELP

Mathematics
1 answer:
vichka [17]3 years ago
5 0

Answer:

120

Step-by-step explanation:

We need the formula of combination:

nCr = \frac{n!}{(n-r)!*r!}

Also we need to understand "factorial" notation, which is the "!" mark. For example, 5! means 5 * 4 * 3 * 2 * 1, and

4! would mean 4 * 3 * 2 * 1

Now we can find out 16C14 by plugging it into the formula and doing the steps shown below:

nCr=\frac{n!}{(n-r)!*r!}\\16C14=\frac{16!}{(16-14)!*14!}\\=\frac{16!}{2!*14!}\\=\frac{16*15*14!}{(2*1)*14!}\\=\frac{16*15}{2}\\=120

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F is the midpoint of AB and E is the midpoint of AC If FE=x+5 and BC=3x+2, What is FE? A)10 B)11 C)12 D)13
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Answer:

Option D is correct.

FE = 13 units

Step-by-step explanation:

As per the statement: F is the midpoint of AB and E is the midpoint of AC.

If FE = x+5 units and

By midpoint theorem of line states that the points on a line segment equally distant from the two endpoints.

Then, by midpoint theorem of line we have;

FE =\frac{1}{2}BC

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x+5 = \frac{1}{2}(3x+2)

Multiply both sides by 2 we getl;

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Using distributive property:

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8 = x

or

x =8 units.

We have to find the value of FE.

FE = x +5 = 8+5 =13 units

Therefore, the value of FE is, 13


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