Answer:
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Answer:
Answer: The mean increases by 3
Step-by-step explanation:
The original data set is
{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}
The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.
The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77
If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80
So in summary so far
old mean = M = 77
new mean = N = 80
The difference in values is N-M = 80-77 = 3
So that's why the mean increases by 3
So if we see the first one (8,4) x=8 and y=4
And we see the 2nd one (4,y) x=4 and y=?
We notice that the value of x its been halved. So y varies with x so y value also has to be halved so y= 2
Answer:
HMM LOOKS LIKE A FRACTION PROBLM IM NOT SURE KIND OF TIERD RN SO UM .........3x+7=3/5 try this in calculated
Step-by-step explanation:
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