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liberstina [14]
3 years ago
12

Find the diagonal of a square whose sides measure 32. Tao

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0

Answer:

Ans.

32 \sqrt{2}

\sqrt{2} a = diagonal \: of \: square \\

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1. Rewrite the expression. Use an exponent, rather than repeated multiplication. (–4)(–4)
AlekseyPX
-4^2 is the same as -4*-4

-4*-4=16

-4^2= 16 

-4^2 is the exponent.

I hope this helps!
~kaikers
4 0
3 years ago
Can someone please help with this ?
olga nikolaevna [1]

Answer:1/32

Step-by-step explanation:

8 0
2 years ago
Point R is on line segment QS. Given QS= 5x-2, QR= 3x-6, and RS=4x-2, determine the numerical length of RS.
pashok25 [27]

Answer:

The numerical length of RS is 10 units

Step-by-step explanation:

* <em>Lets explain How to solve the problem</em>

- Point R is on line segment QS

- The length of QS is (5x - 2)

- The length of QR is (3x - 6)

- The length of RS is (4x - 2)

- <em>The length of QS is the sum of the lengths of QR and RS</em>

∵ QS = QR + RS

∴ (5x - 2) = (3x - 6) + (4x - 2)

- Simplify the right hand side by adding like terms

∴ 5x - 2 = (3x + 4x) + (-6 + -2)

∴ 5x - 2 = 7x + -8 ⇒ (+)(-) = (-)

∴ 5x - 2 = 7x - 8

- Add 8 for both sides

∴ 5x + 6 = 7x

- Subtract 5x from both sides

∴ 6 = 2x

- Divide both sides by 2

∴ x = 3

- <em>To find the length of RS substitute the value of x in its expression</em>

∵ RS = 4x - 2

∵ x = 3

∴ RS = 4(3) - 2 = 12 - 2 = 10

∴ The numerical length of RS is 10 units

8 0
3 years ago
In a parallelogram whose area is 15, the base is represented by x+7 and the altitude x-7. Find the base of parallelogram.
Sati [7]
Area = (base)*(height)
15 = (x+7)(x-7)
(x+7)(x-7) = 15
x^2 - 49 = 15
x^2 - 49+49 = 15+49
x^2 = 64
sqrt(x^2) = sqrt(64)
x = 8 ... note that x can't be negative

If x = 8, then the base is...
x+7 = 8+7 = 15

Therefore the base is 15 units. 
(the height is x-7 = 8-7 = 1 unit)

7 0
2 years ago
What equation represents y=−3x^2+12x−8 in vertex form?
Savatey [412]
Y=3(x+2)^2-20 hope this is right!
7 0
3 years ago
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