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Inga [223]
3 years ago
12

A parabola with vertex (h, k) and a vertical axis of symmetry is modeled by the equation y - k = a(x - h)2. Determine the vertex

for a parabola modeled by y = (x ? 5)2 + 8 A) (5, 8) B) (?5, 8) C) (5, ?8) D) (?5, ?8)
Mathematics
1 answer:
Vilka [71]3 years ago
3 0

Answer:

B. (?5,8)

Step-by-step explanation:

We have been given a parabola with vertex (h, k) and a vertical axis of symmetry is modeled by the equation y-k = a(x-h)^2.

We are also given a parabola y=(x?5)^2+8.

Let us convert our given parabola equation in axis of symmetry equation as shown below:

y=(x?5)^2+8

y-8=(x?5)^2+8-8

y-8=1(x?5)^2

Upon comparing our equation with equation y-k = a(x-h)^2, we can see that h=?5 and k=8.

Therefore, the vertex of the parabola is (?5,8) and option B is the correct choice.

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Juanita borrowed $600 to purchase a new computer. She was charged 7% interest for two years. She used the simple interest formul
Fittoniya [83]

Answer:

The correct formula should be I= 600(0.07)(2). Juanita made a very common error, she didn't put the percentage of interest in decimal form; or she didn't put the percent sign on it so we know to put it in decimal form. Her error will make a big difference; with using her calculations the answer would be $8,400. With the correct formula the answer is $84.

<u>Hope this help!</u> :)

4 0
2 years ago
(a) How many integers in the range 1 through 120 are integer multiples of 2, 3, or 5? keyboard_arrow_down Solution (b) How many
Umnica [9.8K]

Answer:

(a) 88 integers

(b) 92 integers

Step-by-step explanation:

(a) integers whose last digits are divisible by 2 are multiples of two or numbers whose digits ends with zero. So for number 1-120 , all the even numbers which are sixty in number are are multiples of two.

For  3, numbers whose digits sum is divisible by three are multiples of three. 3,6,9,12,15,18,21,24,27,30 are multiples of three from numbers 1-30. we have four 30s in 120. which means numbers of integers will be 10*4 = 40integers. However out of these numbers , half are also integers of 2 which reduces the number added to 20integers.

For 5, numbers whose digits ends with 5 or 0 are multiples of 5. this gives us 24 integers for 1-120. but out of these 24integers, 16 are common integers of 2 and 3 which reduces the number added to 8integers.

Thus from 1-120 the intergers of 2,3 or 5 = 60+20+8 = 88integers.

(b) if we are considering from numbers 1-140;

for 2 we wil have 70 integers,

for 5 we will have 28 integers, but those integers that end with 0 are also integers of 2 which reduces the number added to 14.

For 7, numbers 7,14,21,28,35,42,49,56,63,70 are multiples of three from 1-70. This pattern is repeated from number 71-140. hence we have 20 integers in all. However 12 of the multiples are also multiples of either 2 or 5 which reduces the number to 8 integers.

Thus from 1-140, the integers of 2, 5, or 7 = 70+14+8 = 92integers

3 0
3 years ago
Let f(x) = x - 3 and g(x) = x + 11 find f(x) times g(x)<br><br> What is the answer?
notsponge [240]

f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33

Sorry if its wrong :(

6 0
2 years ago
If you have 2 linear equations and you want to find where they have the same x- and y- value on a graph you look for the
marin [14]

Answer:

Intersection of the two lines.

4 0
2 years ago
A hot air balloon can hold up to 300 pounds of weight. The balloon's pilot weighs 140 pounds. How many 20-pound bags of sand (b)
Anit [1.1K]

Answer:

8 sand bags

Step-by-step explanation:

300 - 140 = 160

160 ÷ 20 = 8

8 sand bags of 20-pounds each.

7 0
2 years ago
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