Question

A parabola with vertex (h, k) and a vertical axis of symmetry is modeled by the equation y - k = a(x - h)2. Determine the vertex for a parabola modeled by y = (x ? 5)2 + 8 A) (5, 8) B) (?5, 8) C) (5, ?8) D) (?5, ?8)

Answer 1

Answer:

B. $(?5,8)$

Step-by-step explanation:

We have been given a parabola with vertex (h, k) and a vertical axis of symmetry is modeled by the equation $y-k = a(x-h)^2$.

We are also given a parabola $y=(x?5)^2+8$.

Let us convert our given parabola equation in axis of symmetry equation as shown below:

$y=(x?5)^2+8$

$y-8=(x?5)^2+8-8$

$y-8=1(x?5)^2$

Upon comparing our equation with equation $y-k = a(x-h)^2$, we can see that $h=?5$ and $k=8$.

Therefore, the vertex of the parabola is $(?5,8)$ and option B is the correct choice.