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Anna71 [15]
3 years ago
10

Simplify a2b3×a5b2​

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

\huge \orange { {a}^{7}  {b}^{5} }

Step-by-step explanation:

\huge {a}^{2}  {b}^{3}  \times  {a}^{5}  {b}^{2}  \\  \\\huge =  {a}^{2}  \times  {a}^{5}   \times {b}^{3}  \times  {b}^{2}  \\ \\\huge =  {a}^{2 + 5}  \times  {b}^{3 + 2}  \\ \\  \huge \red{=  {a}^{7}  {b}^{5} }

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The lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 h
DaniilM [7]

Answer:

Probability that a battery will last more than 19 hours is 0.0668.

Step-by-step explanation:

We are given that the lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 hours.

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So, X ~ N(\mu=16,\sigma^{2} =2^{2})

The z-score probability distribution for normal distribution is given by;

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where, \mu = mean lifetime = 16 hours

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The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, the probability that a battery will last more than 19 hours is given by = P(X > 19 hours)

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Hence, the probability that a battery will last more than 19 hours is 0.0668.

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3 years ago
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Answer:

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