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luda_lava [24]
3 years ago
13

A line has the points (3,7) and (5,19) on it. What is the slope of that line?

Mathematics
1 answer:
Volgvan3 years ago
6 0

Answer:

C) 6

Step-by-step explanation:

19 - 7 = 12

5 - 3 = 2

12/2 = 6

hope this helps :) please mark brainliest if you see fit :)

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Look at image please help I’m struggling only 5 more minutes on this test
Aleonysh [2.5K]

Answer:

.25 dollars

Step-by-step explanation:

divide everything by 4 to get .25

8 0
3 years ago
Read 2 more answers
Grayson went to the grocery store and bought bottles of soda and bottles of juice. Each bottle of soda has 35 grams of sugar and
Illusion [34]

The number of bottles of soda purchased is 10 and the number of bottles of juice purchased is 4.

<u>Step-by-step explanation:</u>

Let us consider the soda bottles as x and juice bottles as y.

From the given data we can derive 2 equations,

35x+15y= 410.    .....(1)

x=y+6.                 ....(2)

Substitute equation (2) in (1),

35(y+6)+15y=410.

35y+ 210+15y=410.

50y+210=410.

50y=410-210.

50y=200.

y=4.

Substitute y value in equation (2),

x=4+6.

x=10.

The number of bottles of soda purchased is 10 and the number of bottles of juice purchased is 4.

4 0
3 years ago
i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.
Natali [406]

Answer:

sin\ \varnothing = \frac{-1}{10}\sqrt 2

cos\ \varnothing = \frac{-7}{10}\sqrt 2

tan\ \varnothing = \frac{1}{7}

cot\ \varnothing = 7

sec\ \varnothing = \frac{-5}{7}\sqrt 2

csc\ \varnothing = -5\sqrt 2

Step-by-step explanation:

Given

N = (-7,-1) --- terminal side of \varnothing

Required

Determine the values of trigonometric functions of \varnothing.

For \varnothing, the trigonometry ratios are:

sin\ \varnothing = \frac{y}{r}       cos\ \varnothing = \frac{x}{r}       tan\ \varnothing = \frac{y}{x}

cot\ \varnothing = \frac{x}{y}       sec\ \varnothing = \frac{r}{x}       csc\ \varnothing = \frac{r}{y}

Where:

r^2 = x^2 + y^2

r = \sqrt{x^2 + y^2

In N = (-7,-1)

x = -7 and y = -1

So:

r = \sqrt{(-7)^2 + (-1)^2

r = \sqrt{50

r = \sqrt{25 * 2

r = \sqrt{25} * \sqrt 2

r = 5 * \sqrt 2

r = 5 \sqrt 2

<u>Solving the trigonometry functions</u>

sin\ \varnothing = \frac{y}{r}

sin\ \varnothing = \frac{-1}{5\sqrt 2}

Rationalize:

sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}

sin\ \varnothing = \frac{-\sqrt 2}{5*2}

sin\ \varnothing = \frac{-\sqrt 2}{10}

sin\ \varnothing = \frac{-1}{10}\sqrt 2

cos\ \varnothing = \frac{x}{r}

cos\ \varnothing = \frac{-7}{5\sqrt 2}

Rationalize

cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}

cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}

cos\ \varnothing = \frac{-7\sqrt 2}{10}

cos\ \varnothing = \frac{-7}{10}\sqrt 2

tan\ \varnothing = \frac{y}{x}

tan\ \varnothing = \frac{-1}{-7}

tan\ \varnothing = \frac{1}{7}

cot\ \varnothing = \frac{x}{y}

cot\ \varnothing = \frac{-7}{-1}

cot\ \varnothing = 7

sec\ \varnothing = \frac{r}{x}

sec\ \varnothing = \frac{5\sqrt 2}{-7}

sec\ \varnothing = \frac{-5}{7}\sqrt 2

csc\ \varnothing = \frac{r}{y}

csc\ \varnothing = \frac{5\sqrt 2}{-1}

csc\ \varnothing = -5\sqrt 2

3 0
3 years ago
Given the equation 6/x=3/k+2, and the constraints x ≠ 0 and k ≠-2, what is x in terms of k?
Veronika [31]

Answer:

A) 2k+4

Step-by-step explanation:

To solve for terms of x, we need to. she sure that x is on its own side while every other term is on the other side.

To start, we will cross multiply. If we have a/b=c/d, then ad=bc

We can perform the same calculation here,

6/x=3/(k+2)

6(k+2)=3x

Divide both sides by 3

2(k+2)=x

x=2k+4

7 0
3 years ago
The area of a rectangle painiting is given by the trinomial x^2-9x-36. what are the possible dimensions of the painting ? use fa
bagirrra123 [75]
<span> (x + 3) • (x - 12)
</span>

The first term is, <span> <span>x2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -9x </span> its coefficient is <span> -9 </span>.
The last term, "the constant", is <span> -36 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span> 

Step-2 : Find two factors of  -36  whose sum equals the coefficient of the middle term, which is  <span> -9 </span>.

<span><span>     -36   +   1   =   -35</span><span>     -18   +   2   =   -16</span><span>     -12   +   3   =   -9   That's it</span></span>


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -12  and  3 
                     <span>x2 - 12x</span> + 3x - 36

Step-4 : Add up the first 2 terms, pulling out like factors :
                    x • (x-12)
              Add up the last 2 terms, pulling out common factors :
                    3 • (x-12)
Step-5 : Add up the four terms of step 4 :
                    (x+3)  •  (x-12)
             Which is the desired factorization

Final result :<span> (x + 3) • (x - 12)</span>
8 0
3 years ago
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