Type 1 hypervisor. also referred to as a
Bare-metal hypervisor
Answer:
int k=0;
for(int i=0;i<=13; i++)
{
if (table[i].getKey().equals(key))
{
k=i;
}
else
{
continue;
}
}
V value= table[k].getValue();
return value;
}
Explanation:
Note table[i] is an entry, and we know the key as it is an argument input to the function. Hence, we find the entry position using the given key, and then find the corresponding value and return it. And this is what is required. There are 14 entries in this hashtable, as known from the question.
...packets. I hope this helps.
I've added my own code in a picture below. I didnt really notice any error, which would cause problems in your code. The main issues I had with your code is purely readability. You should start using the format function along with the curly brackets to concatenate variables into strings. You should also start doing even += 1 instead of even = even + 1. I also tweaked your range function. Simply putting n makes it much easier to read and understand.