Question

Chemical reaction rates are proportional to a rate constant, k, which changes with temperature according to the Arrhenius equation
k=koe^-Q/RT for :
Q=8000 cal/mole
R=1.987 cal/mole K
ko=1200 min-1
Find the value of k for Temperature from 100K to 500K, in 50 degree increments. Create a table of your results.

Answer 1

Answer:

see answer below

Explanation:

the equation is given by

k=ko* e^(-Q/RT)

then replacing the known values

k=1200 min⁻¹ e^[-8000 cal/mole/ (1.987 cal/mole K *T)]

then replacing values of T every 50 K from 100 to 500 K we get the series of values

$\left[\begin{array}{ccc}T&k\\100&3.924*10^{-15} min ^{-1} \\150&2.643*10^{-9} min ^{-1} \\200&2.17*10^{-6} min ^{-1} \\250&1.216*10^{-4} min ^{-1} \\300&1.781*10^{-3} min ^{-1} \\350&0.012 min ^{-1} \\400&0.051 min ^{-1} \\450&0.156 min ^{-1} \\500&0.382 min ^{-1} \end{array}\right]$