He invested two unknown amount that add to $1200.
Let the amount invested at 9% be x.
Let the amount invested at 3% be y.
The amounts add to $1200.
x + y = 1200 First Equation
The profit from the 9% part is 0.09x.
The profit from the 3% part is 0.03y.
The two profits add to $78.
0.09x + 0.03y = 78 Second Equation
We have two equations in two unknowns, so we can solve this problem as a system of equations.
x + y = 1200
0.09x + 0.03y = 78
Multiply the first equation by -0.09 and add to the second equation.
-0.09x - 0.09y = -108
0.09x + 0.03y = 78
----------------------------
-0.06y = -30
Divide both sides by -0.06
y = 500
Now we substitute 500 into y in the first equation.
x + y = 1200
x + 500 = 1200
x = 700
Answer: The amount invested at 9% is $700
Answer:
B. is the answer
Step-by-step explanation:
y>-3x+2
let's do one by one
A. Is 2>-3(-4)+2? negative times negative is positive so 2 is not greater than 12 +2 or 14
B. is 2>-3(4)+2? -3•4=-12 +2 =-10 so yes 2>-10
C. is -2>-3(-2)+2? negative •negative is positive 6+2=8 so -2 is not greater than 8
D. is 0>-3(-4)+2? -•-=+ so 12+2=14. so 0 is not greater than 14
Answer:
x=2.4
Step-by-step explanation:
as the 2 triangles are similar,
therefore ;
Answer:
The question = (7^3)*(7^x)
When multiplying two exponents with the same base, all you do is add the exponents together and keep the same base
Therefore,
(7^3)*(7^x) = 7^(3+x)
Step-by-step explanation:
7^3+x is the answer
