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3 years ago

Help for a brainlist and +10 points added

Mathematics

1 answer:

saul85 [17]3 years ago

7 0

Answer:

B. is the answer

Step-by-step explanation:

y>-3x+2

let's do one by one

A. Is 2>-3(-4)+2? negative times negative is positive so 2 is not greater than 12 +2 or 14

B. is 2>-3(4)+2? -3•4=-12 +2 =-10 so yes 2>-10

C. is -2>-3(-2)+2? negative •negative is positive 6+2=8 so -2 is not greater than 8

D. is 0>-3(-4)+2? -•-=+ so 12+2=14. so 0 is not greater than 14

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The sum of two numbers is 369 the difference of those two numbers is 17 which answer choice shows both numbers

SVETLANKA909090 [29]

Answer:

(176, 193)

Step-by-step explanation:

Well you forgot to put in the choices, but:

The difference between the numbers is 17. Let's call the smaller number x and the bigger one y

(x + y) = 369

y = x + 17

(x + (x + 17)) = 369

2x + 17 = 369

2x = 352

x = 176

y = x + 17 = 193

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A rectangle is the answer

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Harman [31]

Answer:

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Step-by-step explanation:

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3 years ago

Suppose you nake $5 bet on the numbet 0 on a roulette wheel wirh 38 slots labelef 00, 0, 1, 2, 3, .. , 36. If 0 is spun you win

Fynjy0 [20]

Answer:

$13.16

Step-by-step explanation:

For each individual spin, there are two possible outcomes:

- There is a 1 in 38 chance of winning $175.

- There is a 37 in 38 chance of losing $5.

The expected value for each spin is the sum of the products of each outcome by their respective probability.

In 50 spins, the expected value is:

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You can expect to lose $13.16 if you spin the wheel 50 times.

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4 years ago

This morning, some dragons, horses, and chickens were playing in my backyard. I counted 15 heads, 50 legs, and 4 wings. How many

klasskru [66]

We are given

number of heads =15

we know that

any healthy dragon has three heads

horse has 1 head

chicken has 1 head

Let's assume

number of dragons is x

number of horses is y

number of chickens is z

so, we will get

first equation:

$3x+y+z=15$

number of legs =50

any healthy dragon has four legs

chicken has 2 legs

horse has four legs

so, we can get second equation as

$4x+4y+2z=50$

we can simplify it

$2(2x+2y+z)=50$

$2x+2y+z=25$

now, we can find third equation

dragon has two wings

horse has no wings

chicken has two wings

so, we will get third equations as

$2x+0y+2z=4$

now, we can simplify it

$2x+2z=4$

$2(x+z)=4$

$x+z=2$

so, we will get system of equations as

$3x+y+z=15$

$2x+2y+z=25$

$x+z=2$

now, we can use substitution

We can find for z from third equation

$z=2-x$

we can plug this in first equation

$3x+y+2-x=15$

now, we can solve for y

$2x+y+2=15$

$y=13-2x$

now, we can plug this z and y into second equation

$2x+2(13-2x)+2-x=25$

now, we can solve for x

$x-4x+26=23$

$-3x=-3$

$x=1$

now, we can find y and z

$y=13-2x$

we can plug x=1

$y=13-2*1$

$y=11$

$z=2-x$

we can plug x=1

$z=2-1$

$z=1$

Hence ,

number of dragons is 1

number of horses is 11

number of chicken is 1............Answer

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3 years ago