Find P(7).................

Step-by-step explanation: The error occurred when she quoted the Pythagorean theorem. She added up both sides and squared them and made the answer equal to the square of the hypotenuse. She was supposed to have squared them first, before adding up.

The Pythagorean (or Pythagoras) theorem states that the sum of the squares of two sides of a right angled triangle equals the square of the hypotenuse of the triangle. That is, in triangle ABC, if the hypotenuse is given as line AC, the Pythagoras theorem states that

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse and AB and BC are the other two sides.

In Nadia’s solution, if the hypotenuse is given as 73, and the other two sides are 28 and 45, then the Pythagorean theorem properly expressed would be as follows;

73^2 = 28^2 + 45^2

5329 = 784 + 2025

5329 ≠ 2809

As we have determined, writing out the expression as

73^2 = (28 + 45)^2 is very incorrect as this is not the Pythagorean theorem and of course, the triangle cannot have 73 as its hypotenuse as we have determined by properly writing out the Pythagorean theorem.

The correct solution is as follows;

AC^2 = AB^2 + BC^2

AC^2 = 28^2 + 45^2

AC^2 = 784 + 2025

AC^2 = 2809

Add the square root sign to both sides of the equation

AC = 53

Therefore, the hypotenuse is 53 units

4 0

3 years ago

Read 2 more answers

X3= one over eight what's the answer for that?

Black_prince [1.1K]

X^3 = 1/8
x^3 = (1/2)^3
x = 1/2

hope it helps

6 0

3 years ago

1. What is the formula for compound interest?

Rus_ich [418]

Answer:

1. CI = P (1 + $\frac{r}{100}$ )^ n - P

CI = A - P

Where P is Principal

R is interest rate

n is number of years

2. a. Semi annually - four times in a year

b. Monthly - two times in a year

c. annually - once in a year

Step-by-step explanation:

1. Money is said to be lent at compound interest , when the interest has become due at certain fixed period say, one year, half year, etc.., is given not paid to money lender, but is added to sum lent . The amount thus obtained become principal for next month and this process repeat until last period .

i.e CI = Final period - Initial period

or CI = A - P

or CI = P(1+ $\frac{r}{100}$ ) ^n - P

2. (a) Semi annually

A = P (1 + $\frac{r}{4 * 100}$ )^ n × 4

(b) Monthly

A = P (1 + $\frac{r}{2 * 100}$ ) ^ n × 2

(c) Annually

A = P (1 + $\frac{r}{100}$ ) ^ n

3 0

3 years ago