Answer:
Valid is (32,12) , (6,36) , (20,20)
Invalid is (-4,40) , (36,-8), (15,22.5)
Step-by-step explanation:
I just got it right on edmentrum
Gcf is the grouping of all the factors common to both groups
lcm is a group of all the factors that has all the elements of both groups
factor
20x^2y^3=2*2*5*x*x*y*y*y
60x^3y^2=2*2*3*5*x*x*x*y*y
40xy^2=2*2*2*5*x*y*y
the GCF=2*2*5*x*y*y=20xy^2
the LCM=2*2*2*3*5*x*x*x*y*y*y=120x^3y^3
Answer:
D. ∠E ≅ ∠N
Step-by-step explanation:
The pair of sides meet at vertex E in ∆DEF and at vertex N in ∆MNO. Since the sides that make up angles E and N are shown congruent, it is sufficient to show ...
∠E ≅ ∠N
Then the SAS congruence postulate can be claimed.
__
<em>Additional comment</em>
The alternative is to show DF ≅ MO. That would allow you to claim SSS congruence. That is not an answer choice.
Answer:
Hence first graph is the correct answer.
T I
1 28
2 56
3 84
4 112
Step-by-step explanation:
Given that initial amount P = $400
Simple rate of interest = R = 7% = 0.07
Time t= 1,2,3,4 years.
Then apply Simple interest formula to find the total interest earned in the given years.
I=PRT
for t=1 year
I=PRT=400(0.07)(1)=28
for t=2 year
I=PRT=400(0.07)(2)=56
for t=3 year
I=PRT=400(0.07)(31)=84
for t=4 year
I=PRT=400(0.07)(4)=112
Now we have table as shown below:
T I
1 28
2 56
3 84
4 112
Graphing these points we see that obtained graph best matches with First choice .
Hence first graph is the correct answer.