Answer:
c divided by 8
Step-by-step explanation:
<u>We are given:</u>
The function: y = -16t² + 64
where y is the height from ground, t seconds after falling
<u>Part A:</u>
when the droplet would hit the ground, it's height from the ground will be 0
replacing that in the given function:
0 = -16t² + 64
16t² = 64 [adding 16t² on both sides]
t² = 4 [dividing both sides by 16]
t = 2 seconds [taking square root of both sides]
<u>Part B:</u>
for second droplet,
height from ground = 16 feet
time taken = t seconds
acceleration due to gravity = 10 m/s²
initial velocity = 0 m/s
h = ut + (1/2)at² [second equation of motion]
16 = (0)(t) + (1/2)(10)(t²)
16 = 5t²
t² = 16/5
t = 1.8 seconds (approx)
Therefore, the second droplet takes the least amount time to hit the ground
Hello,
If you mean by "using the same material" that all is scaled then
using Thales:
≈179 (m)
Answer:
A hope that helps
Step-by-step explanation:
If n=4 then plug it into the equation.
4-1
3
so your answer is 3
