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zhenek [66]
3 years ago
7

Don't know how to express the value of X as any of those answer choices

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

9514 1404 393

Answer:

  x = √(w(w+z))

Step-by-step explanation:

The idea with a right-triangle figure of this sort is that all of the triangles are similar. Here, x is the short side of ∆ABC, and the hypotenuse of ∆BDC. This suggests you want to write a similarity statement involving the short side and hypotenuse.

  BC/AC = DC/BC . . . . . short side/hypotenuse

  BC² = AC·DC . . . . . . cross multiply

  x² = (w+z)w . . . . . . substitute letter values

Taking the square root and rearranging to the form of the applicable answer choice, this is ...

  \boxed{x=\sqrt{w(w+z)}}

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A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline
dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So P(B) = 0.35

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

So

P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125

Probability

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667

46.67% probability that they flew with airline B.

5 0
3 years ago
Nik and his friend bought shares of stock at the rate of $32 per share. For $3,520, Nik's friend bought 10 fewer shares than Nik
Svetradugi [14.3K]

Answer:

#1-List all outcomes for choosing the digit. *

0)

O

A: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

O

B: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

O

C: 1, 2, 3, 4, 5, 6, 7, 8, 9

OD: a number

O

Both B and C

Step-by-step explanation:

7 0
3 years ago
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