SA=2pir^2+2hpir=2pir(r+h)
h=2r=2(2x+3)=4x+6
SA=2pi(2x+3)(2x+3+4x+6)
SA=(4x+6)(pi)(6x+9)
SA=24πx²+27πx+54π
Answer:
(
x−
2
)
(
x
+
4
)
Step-by-step explanation:
The mass lost by Darragh's coin is 0.164 g
<u>Solution:</u>
Given that Darragh has a Golden Eagle coin in his collection with a mass of 13.551 g
An uncirculated Golden Eagle coin has a mass of 13.715 g
To find: mass lost by Darragh's coin
From given question,
Darrangh has coin of mass = 13.551 g
Golden Eagle coin mass = 13.715 g
Darrangh's coin lost mass = 13.715 - 13.551 = 0.164
Thus mass lost by Darragh's coin is 0.164 g
∠C is 148°.
Step-by-step explanation:
- Step 1: Given ∠A = 16° and ∠B = (10x - 64)°. Also, AC = BC. Now, the angles opposite to equal sides of a triangle are equal. So ∠B = 16°
- Step 2: Sum of angles of a triangle is 180°
⇒ 16° + 16° + ∠C = 180°
⇒ ∠C = 180 - 32 = 148°
