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IceJOKER [234]
3 years ago
5

Soup ordinarily priced at two cans for 33 cents, may be purchased in lots of a dozen for $1.74. What are the savings per can whe

n purchased this way?
A. 8 cents B. 2/3 cents C. 9 1/2 cents D. 2 cents

Thx! ASVAB Q. :)
Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0

i think it would be d.) 2 cents

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HELP PLEASE ITS JUST ONE QUESTION
Nady [450]

Answer:

y = 2x - 1

Step-by-step explanation:

The given line is y = 2x - 6.

It is in the y = mx + b form, where m is the slope, so its slope is 2.

We need a line that passes through point P(3, 5) and has slope 2.

y = mx + b

Put the slope in m.

y = 2x + b

Use the given point with x = 3 and y = 5 and solve for b.

5 = 2(3) + b

b + 6 = 5

b = -1

The equation is

y = 2x - 1

4 0
3 years ago
(25 points)
Licemer1 [7]
Here, y = -15 with x = -20
LCM of 15 & 20 is 60, so divide 15 & 20 from 60, 
60/15 = 4 & 60/20 = 3

Now, multiply the results with intial values, 
4y = 3x
y = 3/4 x

When y = 12, 
x = 12 * 4/3
x = 48 / 3
x = 16

In short, Your Answer would be 16

Hope this helps!

8 0
3 years ago
In a group of 120 farmers, 65 grow maize and 75 grow cassava. Of these 35 grow both maize and cassava.
Simora [160]
30 farmers grow it I think.
5 0
4 years ago
Marco wants to take a taxi cab ride if the cost to ride is 7.00 with the cost per m is 0.25 per mile and mr. o can only spend 30
77julia77 [94]

Each ride has a fixed cost of 7 and a cost that increases proportionally to the distance travelled of 0.25 per mile. Therefore the total cost of the ride is:

\text{ cost(x)}=0.25\cdot x+7

Where "x" is the distance in miles. Marco can only spend 30 on his ride, therefore the cost must be less or equal to that value.

\begin{gathered} \text{ cost(x)}\leq30 \\ 0.25\cdot x+7\leq30 \end{gathered}

We can solve the linear equation by isolating the "x" variable on the left side.

\begin{gathered} 0.25\cdot x\leq30-7 \\ 0.25\cdot x\leq23 \\ x\leq\frac{23}{0.25} \\ x\leq92 \end{gathered}

Marco's travel must be shorter or equal to 92 miles.

6 0
1 year ago
Select all the correct locations on the table.
zmey [24]

Answer:

Situation 1 is exponential decay. Situation 2 is linear. Situation 3 is exponential growth.

Step-by-step explanation:

Situation 1 is exponential decay because it declined in a non linear way.

600-480=120 480-364=116

Situation 2 is linear because when it declined it has a dependent to another.

400-340=60 340-280=60

Situation 3 is exponential growth because is increases.

7 0
3 years ago
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