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4 years ago

12

What is the simplified form of this expression?

xFormula1" title=" \frac{4x3y3}{8x5y2} " alt=" \frac{4x3y3}{8x5y2} " align="absmiddle" class="latex-formula">

1 answer:

jek_recluse [69]4 years ago

6 0

Answer:

something

Step-by-step explanation:

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Given △ABC, sin(A) = <br><br> A. cos(B)<br> B. sin(B)<br> C. cos(C)<br> D. tan (C)

irinina [24]

the answer is cos(C).

7 0

4 years ago

Read 2 more answers

Evaluate the summation from n equals 1 to infinity of the quotient of 3 and 2 raised the quantity n minus 1 power

Shalnov [3]

Answer:

3*∑ (1/2)^n = 6

Step-by-step explanation:

We have the summation from n = 1 to n = ∞, for:

∑ 3/(2)^(n - 1)

We know that the summation between k = 0, and k = N - 1 for:

∑ r^k = (1 - r^N)/(1 - r)

if we have the summation between k = 0 and k = ∞ - 1 = ∞

(here we used that ∞ is really big, then ∞ - 1 = ∞)

In the numerator we will have the term r^∞, if 0 < r < 1, then r^∞ = 0.

Then if we assume that 0 < r < 1 we can write:

∑ r^k = 1/(1 - r)

In our case, we can rewrite our summation as:

3*∑ (1/2)^n

for n = 0 to n = ∞

You can see that i changed the limits for n, this does not really matter because we are summing between a number and infinity, the only thing you need to take care is that now the power is n, instead of (n - 1)

Then we have r = (1/2) which is clearly smaller than 1.

then (1/2)

Then this summation is equal to:

3*∑ (1/2)^n = 3*( 1/(1 - 1/2)) = 3*( 1/( 2/2 - 1/2)) = 3*( 1/(1/2)) = 3*2 = 6

3*∑ (1/2)^n = 6

5 0

3 years ago

4b - a if a=2 b=4 find its answer

romanna [79]

Answer:

14

Step-by-step explanation:

if b=4 and a=2, then you substitute both those values into the equation, turning (4b - a) into (4*4 - 2), then you use order of operations, meaning you multiply the 4 times the 4, which turns it into 16-2, and then subtract 2 to finally reach your answer of 14.

5 0

3 years ago

2^5×8^4/16=2^5×(2^a)4/2^4=2^5×2^b/2^4=2^c<br>A=<br>B=<br>C= <br>Please I'm gonna fail math

aleksley [76]

9514 1404 393

Answer:

a = 3, b = 12, c = 13

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)/(a^c) = a^(b-c)

(a^b)^c = a^(bc)

___

You seem to have ...

$\dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)$

_____

<em>Additional comment</em>

I find it easy to remember the rules of exponents by remembering that <em>an exponent signifies repeated multiplication</em>. It tells you how many times the base is a factor in the product.

$2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}$

Multiplication increases the number of times the base is a factor.

$(2\cdot2\cdot2)\times(2\cdot2)=(2\cdot2\cdot2\cdot2\cdot2)\\\\2^3\times2^2=2^{3+2}=2^5$

Similarly, division cancels factors from numerator and denominator, so decreases the number of times the base is a factor.

$\dfrac{(2\cdot2\cdot2)}{(2\cdot2)}=2\\\\\dfrac{2^3}{2^2}=2^{3-2}=2^1$

5 0

3 years ago

Ab (3a-5b) equals to?

Aleks04 [339]

Answer:

3a^2b-5ab^2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers