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3 years ago

Which phase of mitosis is the last phase that chromatids are together

Biology

1 answer:

Vladimir [108]3 years ago

4 0

Answer:

Metaphase

Explanation:

The M phase of the cell cycle is the phase during which the nuclear content and cellular content is distributed. The distribution of the nuclear content takes place in four phases: prophase, metaphase, anaphase and telophase.

The homologous chromosomes are aligned at the equatorial plate during the metaphase after which the chromosomes separate. The phase during which the separation of the chromosomes takes place is known as anaphase so the phase before the anaphase is the phase during which the chromatids are not separated that is the metaphase.

Thus, metaphase is the correct answer.

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A__ or change in a gene causes the disease hemophilia in 30% of cases of the disease.

sukhopar [10]

Answer:

Hemophilia A is caused by disruptions or changes (mutations) of the F8 gene located on the X chromosome. Approximately 70% of cases are inherited as an X-linked recessive trait. In the remaining 30%, cases occur spontaneously (i.e. new mutation) without a previously family history of the disorder.

Explanation:

hope this helps

4 0

3 years ago

If you have an idea to improve a complex software process at work, what is the most effective way to communicate this idea?

ludmilkaskok [199]

Answer: Option D

Explanation:

If there is a certain idea regarding any process which can be improved then the thought to improve it should be first shared with the boss of the company.

Firstly, the person sharing the thought should himself be sure about the thought that he is going to present in front of the boss.

The thought regarding the improvement of the software process should be first written in an organized way and presented to the boss.

7 0

3 years ago

You are living next to a field that is burning. The smoke is blowing towards your neighborhood. You are outside and there is so

arlik [135]

Answer:

Hello now,

The human body system that would be most affected in this scenario would be B, the Respiratory and circulatory system.

3 0

3 years ago

On the Galapagos Islands, Darwin observed tortoises with domed and saddle-shaped shells. How did Darwin's observations of these

photoshop1234 [79]

Answer:

The correct answer would be C. The tortoises provided evidence that different species have adaptations suited to their particular environments.

Darwin observed that how different environment on different island lead to the development of different species as a result of adaptations and natural selection.

For example, tortoise inhabiting well-watered islands which used to have short and cropped vegetation had developed a dome-shaped shell.

In contrast, the tortoise inhabiting the arid islands had developed saddle-shaped shells. It is because they needed to stretch their necks in order to reach branches of cactus and other vegetation available in the area.

Consequently, they developed long necks and high peak to the front edges of their shells. It made it possible for them to stretch their heads vertically.

7 0

3 years ago

Read 2 more answers

1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently

maria [59]

Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

Available data:

Flower position: Axial (A) is dominant to Terminal (a)

Stem length: Tall (T) is dominant to dwarf (t)

Seed shape: Round (R) is dominant to wrinkled (r)

Cross:

Parental) AaTtDd x AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

AA= 1/4

Aa =2/4

aa = 1/4

TT = 1/4

Tt = 2/4

tt = 1/4

DD = 1/4

Dd = 2/4

dd = 1/4

This is the same as developing a Punnett square for each gene separately.

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4 x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

4 0

3 years ago

Read 2 more answers