Answer:
D. The work shown above is correct, and
may not be simplified further.
Step-by-step explanation:
![\sqrt[4]{y^{23} } = \sqrt[4]{y^4 . y^4 . y^4.y^4.y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E%7B23%7D%20%7D%20%3D%20%5Csqrt%5B4%5D%7By%5E4%20.%20y%5E4%20.%20y%5E4.y%5E4.y%5E3%7D)
![\sqrt[4]{y^4. y^4.y^4. y^4.y^3} = y^5 . \sqrt[4]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E4.%20y%5E4.y%5E4.%20y%5E4.y%5E3%7D%20%3D%20y%5E5%20.%20%5Csqrt%5B4%5D%7By%5E3%7D)
When we simplify, we get
![\sqrt[4]{y^{23} } = y^5.\sqrt[4]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E%7B23%7D%20%7D%20%3D%20y%5E5.%5Csqrt%5B4%5D%7By%5E3%7D)
The answer: D. The work shown above is correct, and
may not be simplified further.
Thank you.
Answer:(-1,2)
Step-by-step explanation:
After you re-arrange the equation, you'll find out that you got y=3x+6....okay, this equation is a linear equation, you can use y=mx+b {where m=3, and b=6}. then to find the co-ordinate of (x,y) which is the point, substitute 1,2,3,4.... for x in 'y=3x+6' to figure out the co-ordinate of y.
answer: (1,14), (2,16), (3,19), (4,22)
Answer:
u use the closest number to the number u are rounding up to round it up.if it is 0-4 u round it to 0and add to the number while if it is 5-9 u round it up to 1 and add to the number.after all rounding up the number used to round up downwards will be converted to 0s
the correct answer for this is the last choice:
It is incorrect because the length of the unknown side is the square root of 7,225.