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Dvinal [7]
2 years ago
5

Help plz no links unhelpful answers will get reported use formulas plz. I'm being gneerous

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
7 0

Answer:

what's the question?? I b.d ont get it

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you find a shirt You want to buy and the original price is $26.95 if the shirt is marked as 20% off find the discount and the sa
Scrat [10]
100% - 20% = 80%

$26.95 * 80% = $21.56

You multiply by 80% because you are taking 20% off and now want to know what 80% of the price will be.
5 0
3 years ago
Read 2 more answers
You play a game that involves drawing two numbers from a hat. There are 25 pieces of paper numbered 1 to 25 in the hat. Each num
Sergeu [11.5K]

Answer:so it’s 5

Step-by-step explanation:

It’s 2 divided by 10 = 5

3 0
2 years ago
Write an equation of the line in slope-intercept from?
netineya [11]

Answer:

y=-\frac{3}{2}x+2

Step-by-step explanation:

This is for the first question.

Slope-intercept is:

y=mx+b

m - slope

b - y-intercept

We are given the slope of -\frac{3}{2} and a y-intercept of 2.

Plug in the values:

y=mx+b\rightarrow\boxed{y=-\frac{3}{2}x+2}

Hope this helps.

4 0
3 years ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
Show work. This is a BC calculus problem.
stepan [7]

Answer:

D.

Step-by-step explanation:

Remember that the limit definition of a derivative at a point is:

\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}

Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:

\displaystyle{\frac{d}{dx}[f(1)]= \lim_{x \to 1}\frac{\ln(x+1)-\ln(2)}{x-1}}

Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).

The answer will thus be D.

5 0
2 years ago
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